- Add \(\frac{1}{2}\) to both sides of the equation to isolate the term with \(b\).
- Simplify the right side of the equation to get \(-\frac{1}{3}\).
- Multiply both sides by the reciprocal \(-\frac{8}{3}\) to solve for \(b\).
- The solution for \(b\) is \(\boxed{\frac{8}{9}}\).
Explanation
- Problem Analysis and Strategy
The objective is to solve the linear equation \(-\frac{1}{2} - \frac{3}{8}b = -\frac{5}{6}\) for the variable \(b\). Our goal is to isolate \(b\) by performing algebraic operations on both sides of the equation. We will first isolate the term containing \(b\) by adding a constant to both sides, simplify the resulting arithmetic expression, and finally solve for \(b\) by multiplying by the reciprocal of its coefficient.
- Isolating the Term with \(b\)
To begin isolating the term with \(b\), we add \(\frac{1}{2}\) to both sides of the equation:
\[-\frac{3}{8}b = -\frac{5}{6} + \frac{1}{2}\]
Next, we perform the addition on the right side. To add \(-\frac{5}{6}\) and \(\frac{1}{2}\), we find a common denominator, which is \(6\). Since \(\frac{1}{2} = \frac{3}{6}\), the expression becomes:
\[-\frac{3}{8}b = -\frac{5}{6} + \frac{3}{6}\]
\[-\frac{3}{8}b = -\frac{2}{6}\]
Simplifying the fraction \(-\frac{2}{6}\) by dividing the numerator and denominator by their greatest common divisor, \(2\), we get:
\[-\frac{3}{8}b = -\frac{1}{3}\]
- Solving for \(b\)
Now we solve for \(b\) by multiplying both sides of the equation by the reciprocal of \(-\frac{3}{8}\), which is \(-\frac{8}{3}\):
\[b = \left(-\frac{1}{3}\right) \times \left(-\frac{8}{3}\right)\]
Performing the multiplication:
\[b = \frac{(-1) \times (-8)}{3 \times 3} = \frac{8}{9}\]
The value of \(b\) is \(\frac{8}{9}\). This fraction is in its simplest form as \(8\) and \(9\) share no common factors other than \(1\).
Examples
In financial modeling, you might encounter situations where a debt or budget adjustment is represented by a linear equation. For instance, if a company's total adjustment is defined by a constant reduction and a variable portion scaled by a factor, setting this equal to a target outcome helps determine the necessary change. This problem demonstrates the process of isolating the unknown variable, a fundamental skill in solving for target metrics in any quantitative analysis.