- For a square root function \(\sqrt{x+1} - 3\), the radicand must satisfy the condition \(x + 1 \geq 0\).
- Solving the inequality gives \(x \geq -1\).
- In interval notation, this represents the set \([-1, \infty)\).
- Therefore, the correct choice is \(\boxed{[-1, \infty)}\).
Explanation
- Analyzing the Function and Defining the Domain Condition
The given function is \(f(x) = \sqrt{x+1} - 3\). A square root function \(\sqrt{g(x)}\) is defined for real numbers only when the expression inside the square root, the radicand, is non-negative. This condition is necessary because the square root of a negative number is not a real number. In this problem, the radicand is \(x+1\).
- Solving the Inequality for the Domain
To find the domain, we must solve the inequality \(x + 1 \geq 0\). Subtracting 1 from both sides of the inequality, we get \(x \geq -1\). This means the function \(f(x)\) is defined for all values of \(x\) that are greater than or equal to -1.
- Determining the Correct Option
The set of all values of \(x\) satisfying \(x \geq -1\) can be written in interval notation as \([-1, \infty)\). Comparing this result to the given options:
- \([3, \infty)\)
- \([-3, \infty)\)
- \([1, \infty)\)
- \([-1, \infty)\)
The correct option is the one corresponding to \([-1, \infty)\).
Examples
The concept of a domain is crucial when working with physical measurements. For example, if you are modeling the time it takes for an object to fall a certain distance \(h\) given by the formula \(t(h) = \sqrt{\frac{2h}{g}}\) (where \(g\) is gravity), the domain of the function represents all possible heights \(h\) that make sense in this context. Since you cannot have a negative distance, the domain is \(h \geq 0\). Understanding how to calculate the domain ensures that your mathematical model accurately reflects real-world constraints.