- Identify the common term \(x^2\) in the system \(\begin{cases} x^2 + y^2 = 25 \ x^2 + 7y = 37 \end{cases}\).
- Subtract the equations to eliminate \(x^2\), resulting in the quadratic \(y^2 - 7y + 12 = 0\).
- Solve for \(y\) by factoring to obtain \(y = 3\) or \(y = 4\).
- Calculate the corresponding \(x\) values for each \(y\) and conclude the solution pairs as \(\boxed{{(4, 3), (-4, 3), (3, 4), (-3, 4)}}\).
Explanation
- Analyzing the System of Equations
The objective is to find all real pairs \((x, y)\) that satisfy the following system of nonlinear equations:
\[ \begin{cases} x^2 + y^2 = 25 \quad (1) \ x^2 + 7y = 37 \quad (2) \end{cases} \]
By analyzing the system, we notice that both equations contain the term \(x^2\). This allows us to use the elimination method by subtracting one equation from the other to remove \(x^2\) and reduce the problem to solving for \(y\).
- Eliminating \(x^2\) and Solving for \(y\)
To eliminate \(x^2\), we subtract equation (2) from equation (1):
\[(x^2 + y^2) - (x^2 + 7y) = 25 - 37\]
This simplifies to:
\[y^2 - 7y = -12\]
Adding 12 to both sides gives the quadratic equation:
\[y^2 - 7y + 12 = 0\]
We can factor this quadratic expression:
\[(y - 3)(y - 4) = 0\]
Setting each factor to zero, we find the potential values for \(y\):
\[y = 3 \quad \text{or} \quad y = 4\]
- Solving for \(x\) and Finding All Solution Pairs
Now, we substitute each value of \(y\) back into one of the original equations to find the corresponding values of \(x\). Let's use equation (2), \(x^2 + 7y = 37\), which implies \(x^2 = 37 - 7y\).
Case 1: If \(y = 3\):
\[x^2 = 37 - 7(3) = 37 - 21 = 16\]
Taking the square root of both sides, we get \(x = 4\) or \(x = -4\). This gives two solution pairs: \((4, 3)\) and \((-4, 3)\).
Case 2: If \(y = 4\):
\[x^2 = 37 - 7(4) = 37 - 28 = 9\]
Taking the square root of both sides, we get \(x = 3\) or \(x = -3\). This gives two more solution pairs: \((3, 4)\) and \((-3, 4)\).
- Conclusion and Verification
Combining the results, we have identified four pairs \((x, y)\) that satisfy both equations in the system. The solutions are:
\((4, 3)\), \((-4, 3)\), \((3, 4)\), and \((-3, 4)\).
Each pair can be verified:
For \((4, 3)\): \(4^2 + 3^2 = 16 + 9 = 25\) and \(4^2 + 7(3) = 16 + 21 = 37\).
For \((3, 4)\): \(3^2 + 4^2 = 9 + 16 = 25\) and \(3^2 + 7(4) = 9 + 28 = 37\).
The negative cases hold symmetrically since \(x\) is squared.
The solution set is \(\boxed{{(4, 3), (-4, 3), (3, 4), (-3, 4)}}\).
Examples
In physics, solving a system like this can represent finding intersection points of paths or balancing conditions. For example, if \(x^2 + y^2 = 25\) represents the circular orbit of an object and \(x^2 + 7y = 37\) represents a trajectory constraint, these solutions represent the specific coordinates in a coordinate plane where the object satisfies both physical constraints simultaneously. This helps engineers and scientists predict object positions or verify design parameters.