Sodium hydroxide $( NaOH )$ is a strong base that is very corrosive. What is the mass of $2.75 imes 10^{-4}$ moles of NaOH?


A$6.50 imes 10^{-2} g NaOH$
B$3.24 imes 10^{-3} g NaOH$
C$6.10 imes 10^{-2} g NaOH$
D$1.10 imes 10^{-2} g NaOH$

Verified Answer :

  • Identify the atomic masses of Na (\(22.99 \text{ g/mol}\)), O (\(16.00 \text{ g/mol}\)), and H (\(1.01 \text{ g/mol}\)).
  • Calculate the molar mass of NaOH: \(M = 22.99 + 16.00 + 1.01 = 40.00 \text{ g/mol}\).
  • Use the formula \(m = n \times M\) with \(n = 2.75 \times 10^{-4} \text{ mol}\) to find the mass: \(m = 2.75 \times 10^{-4} \times 40 = 1.10 \times 10^{-2} \text{ g}\).
  • Conclude that the correct answer is \(d\), corresponding to \(\boxed{1.10 \times 10^{-2} \text{ g } NaOH}\).

Explanation

  1. Analysis of the Problem

To determine the mass of \(2.75 \times 10^{-4}\) moles of sodium hydroxide (NaOH), we need to relate the number of moles to the mass using the molar mass. The formula for mass is \(m = n \times M\), where \(n\) is the number of moles and \(M\) is the molar mass in grams per mole. The molar mass of a compound is the sum of the atomic masses of its constituent elements. For NaOH, the elements are sodium (Na), oxygen (O), and hydrogen (H). Using the standard atomic masses (Na: \(22.99 \text{ g/mol}\), O: \(16.00 \text{ g/mol}\), H: \(1.01 \text{ g/mol}\)), we can determine the molar mass of NaOH.

  1. Calculating Molar Mass of NaOH

The molar mass \(M\) of NaOH is calculated by summing the atomic masses of sodium, oxygen, and hydrogen:
\[M = 22.99 \text{ g/mol} + 16.00 \text{ g/mol} + 1.01 \text{ g/mol} = 40.00 \text{ g/mol}.\]
With the molar mass determined to be \(40.00 \text{ g/mol}\), we can proceed to calculate the total mass of the given substance.

  1. Calculating Mass and Selecting the Correct Option

Given the number of moles \(n = 2.75 \times 10^{-4} \text{ mol}\), we use the mass formula \(m = n \times M\):
\[m = (2.75 \times 10^{-4} \text{ mol}) \times (40.00 \text{ g/mol})\]
\[m = 2.75 \times 40.00 \times 10^{-4} \text{ g}\]
\[m = 110.00 \times 10^{-4} \text{ g} = 1.10 \times 10^{-2} \text{ g}.\]
The calculated mass is \(1.10 \times 10^{-2} \text{ g}\), which matches option (d).

Examples

In a chemical laboratory, knowing the exact mass of a substance is critical for experiments. For instance, when preparing a buffer solution, chemists often weigh precise amounts of bases like sodium hydroxide. By converting moles, which are used to represent chemical quantities, into grams, which can be measured on a balance, scientists ensure the accuracy and safety of their chemical reactions. Understanding this conversion is a fundamental skill in chemistry for preparing reagents for medical research or industrial processing.