The graph of $f(x)=\frac{9 x^2+36 x+41}{3 x+5}$ has an oblique asymptote at $y=3 x+k$. What is the value of $k$?
To find the oblique asymptote of the function \(f(x) = \frac{9x^2 + 36x + 41}{3x + 5}\), we perform polynomial long division of the numerator by the denominator. An oblique asymptote occurs when the degree of the numerator is exactly one higher than the degree of the denominator, and it is given by the quotient of this division.
We divide \(9x^2 + 36x + 41\) by \(3x + 5\):
Thus, the function can be rewritten as:
\(f(x) = 3x + 7 + \frac{6}{3x + 5}\).
As \(x \to \pm \infty\), the term \(\frac{6}{3x + 5}\) approaches 0. Therefore, the function \(f(x)\) approaches the linear expression \(y = 3x + 7\). Comparing this to the given form \(y = 3x + k\), we can identify that \(k = 7\).
The value of \(k\) in the oblique asymptote \(y = 3x + k\) is \(\boxed{7}\).
Oblique asymptotes are vital in engineering and economics, particularly when analyzing growth trends. For instance, in supply chain management, if the total cost of production follows a rational function like this one, the oblique asymptote represents the 'variable cost per unit' trend as production scales up, allowing managers to predict long-term operational costs effectively. Understanding these limits helps in making informed decisions about scaling and pricing in various industries.