Which expression is equivalent to $\frac{3}{2}$?


A$\frac{3 y}{2 y-6}+\frac{9}{6-2 y}$
B$\frac{9}{y}-\frac{6}{y+2}$
C$\frac{3 y}{2 y-6}+\frac{9}{2 y-6}$
D$\frac{6}{2 y}-\frac{9 y}{2-3 y}$

Verified Answer :

  • Analyze the given rational expressions to find which one simplifies to \(\frac{3}{2}\).
  • Simplify the first expression \(\frac{3y}{2y-6} + \frac{9}{6-2y}\) by rewriting the second denominator as \(-(2y-6)\).
  • Combine the terms to get \(\frac{3y-9}{2y-6}\) and factor to identify common terms: \(\frac{3(y-3)}{2(y-3)}\).
  • Simplify by canceling \((y-3)\) to obtain \(\boxed{\frac{3y}{2y-6} + \frac{9}{6-2y}}\).

Explanation

  1. Problem Analysis and Candidate Expressions

We are tasked with determining which of the four given rational expressions simplifies to the constant value \(\frac{3}{2}\). The four candidates are:

  1. \(\frac{3y}{2y-6} + \frac{9}{6-2y}\)
  2. \(\frac{9}{y} - \frac{6}{y+2}\)
  3. \(\frac{3y}{2y-6} + \frac{9}{2y-6}\)
  4. \(\frac{6}{2y} - \frac{9y}{2-3y}\)

We will simplify each expression one by one to see which one results in \(\frac{3}{2}\).

  1. Evaluating the First Expression

Let's examine the first expression:
\[ \frac{3y}{2y-6} + \frac{9}{6-2y} \]
Notice that the second denominator \(6-2y\) can be written as \(-(2y-6)\). Thus, the expression becomes:
\[ \frac{3y}{2y-6} + \frac{9}{-(2y-6)} = \frac{3y}{2y-6} - \frac{9}{2y-6} \]
Now, combine the terms over the common denominator \(2y-6\):
\[ \frac{3y-9}{2y-6} \]
Factor both the numerator and the denominator:
\[ \frac{3(y-3)}{2(y-3)} \]
Assuming \(y eq 3\), we can cancel out the common factor \((y-3)\):
\[ \frac{3}{2} \]
This matches the target value! We have found the correct expression.

  1. Verification of Other Expressions

For completeness, let's briefly look at the others to ensure they do not simplify to \(\frac{3}{2}\):

  • The second expression \(\frac{9}{y} - \frac{6}{y+2}\) simplifies to \(\frac{9(y+2) - 6y}{y(y+2)} = \frac{3y+18}{y^2+2y}\), which clearly depends on \(y\).
  • The third expression \(\frac{3y+9}{2y-6} = \frac{3(y+3)}{2(y-3)}\), which also depends on \(y\).
  • The fourth expression \(\frac{6}{2y} - \frac{9y}{2-3y} = \frac{3}{y} - \frac{9y}{2-3y} = \frac{3(2-3y)-9y^2}{y(2-3y)} = \frac{6-9y-9y^2}{2y-3y^2}\), which again depends on \(y\).

Only the first expression is equivalent to \(\frac{3}{2}\).

  1. Final Conclusion

The expression \(\frac{3y}{2y-6} + \frac{9}{6-2y}\) simplifies correctly to the constant \(\frac{3}{2}\). Therefore, this is the correct choice. The final answer is \(\boxed{\frac{3y}{2y-6} + \frac{9}{6-2y}}\).

Examples

In algebra, simplifying rational expressions is a vital skill used to analyze complex systems, such as finding equilibrium points in economic models or solving for variables in physical science formulas. By reducing complicated-looking fractions to a single constant, we can easily see how different components interact and cancel each other out, leading to a much simpler and more useful model for predicting real-world outcomes.