Select the correct answer.



What is the solution to the equation $|5-x|=13$ ?


A$x=-18$
B$x=8$
C$x=-8$ or $x=18$
D$x=-18$ or $x=8$

Verified Answer :

  • The absolute value equation \(|5 - x| = 13\) is split into two linear equations: \(5 - x = 13\) and \(5 - x = -13\).
  • Solving the first equation yields \(5 - x = 13 \implies -x = 8 \implies x = -8\).
  • Solving the second equation yields \(5 - x = -13 \implies -x = -18 \implies x = 18\).
  • Comparing these results with the given options, the correct choice is \(x = -8\) or \(x = 18\).
  • Final answer: \(\boxed{x = -8 \text{ or } x = 18}\).

Explanation

  1. Analyzing the Absolute Value Equation

To solve the equation \(|5 - x| = 13\), we first recall the definition of an absolute value equation. For any expression \(u\), the equation \(|u| = k\) (where \(k > 0\)) is equivalent to two separate cases: \(u = k\) or \(u = -k\). In this problem, our expression is \(u = 5 - x\) and our constant is \(k = 13\). Therefore, the equation splits into two linear equations.

  1. Solving the First Case

The first case is \(5 - x = 13\). To solve for \(x\), we subtract 5 from both sides:
\(-x = 13 - 5\)
\(-x = 8\)
Multiplying by -1, we find:
\(x = -8\)

  1. Solving the Second Case

The second case is \(5 - x = -13\). To solve for \(x\), we subtract 5 from both sides:
\(-x = -13 - 5\)
\(-x = -18\)
Multiplying by -1, we find:
\(x = 18\)

  1. Conclusion and Final Answer

By solving the absolute value equation, we have identified two possible values for \(x\): \(x = -8\) and \(x = 18\). Looking at the provided options, the correct choice is \(x = -8\) or \(x = 18\).

Examples

The concept of absolute value is essential in measuring distances or differences, as these values are always non-negative. For instance, if you are measuring the temperature deviation from a set point (e.g., 5 degrees) in a laboratory experiment, the absolute value helps you quantify how far the current temperature is from the target, regardless of whether it is warmer or colder. Understanding this allows you to determine the range of acceptable temperatures needed for a process to remain stable.