What is the term in the expansion of $(x-2 y)^{13}$?


A$-329,472 x^5 y^8$
B$329,472 x^5 y^8$
C$-41,184 x^8 y^5$
D$41,184 x^8 y^5$

Verified Answer :

  • Use the binomial theorem formula to identify the general term as \(T_{k+1} = \binom{13}{k} (-2)^k x^{13-k} y^k\).
  • Calculate the terms for \(k=8\) and \(k=5\) using the binomial coefficients and the power of \(-2\).
  • For \(k=8\), the term is \(1,287 \times 256 x^5 y^8 = 329,472 x^5 y^8\).
  • For \(k=5\), the term is \(1,287 \times -32 x^8 y^5 = -41,184 x^8 y^5\).
  • Both options b and c are correct: \(\boxed{\text{b and c}}\).

Explanation

  1. Understanding the Binomial Expansion Formula

The binomial theorem states that the expansion of \((a+b)^n\) is given by:
\[(a+b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k\]
In this problem, we are looking for a term in the expansion of \((x - 2y)^{13}\). Here, \(a = x\), \(b = -2y\), and \(n = 13\). The general term in the expansion, denoted by \(T_{k+1}\), is given by:
\[T_{k+1} = \binom{13}{k} x^{13-k} (-2y)^k\]
This can be simplified by separating the variables and the constant coefficient:
\[T_{k+1} = \binom{13}{k} x^{13-k} (-2)^k y^k = \binom{13}{k} (-2)^k x^{13-k} y^k\]
To determine the potential terms, we test values of \(k\) that match the powers of \(x\) and \(y\) in the provided options.

  1. Calculating the Terms for k=8 and k=5

The provided options are categorized by powers of \(x\) and \(y\). Specifically, we have terms involving \(x^5 y^8\) and \(x^8 y^5\).
Matching \(x^{13-k} y^k\) to \(x^5 y^8\) gives \(k = 8\).
Matching \(x^{13-k} y^k\) to \(x^8 y^5\) gives \(k = 5\).
First, for \(k = 8\):
The binomial coefficient \(\binom{13}{8} = \frac{13 \times 12 \times 11 \times 10 \times 9}{5 \times 4 \times 3 \times 2 \times 1} = 1,287\).
The power of the coefficient \((-2)^8 = 256\).
The numerical coefficient is \(\binom{13}{8} \times (-2)^8 = 1,287 \times 256 = 329,472\).
Thus, the term is \(329,472 x^5 y^8\).

Second, for \(k = 5\):
The binomial coefficient \(\binom{13}{5} = \binom{13}{8} = 1,287\).
The power of the coefficient \((-2)^5 = -32\).
The numerical coefficient is \(\binom{13}{5} \times (-2)^5 = 1,287 \times -32 = -41,184\).
Thus, the term is \(-41,184 x^8 y^5\).

  1. Conclusion

Comparing our results with the provided options:

A\(-329,472 x^5 y^8\)
B\(329,472 x^5 y^8\)
C\(-41,184 x^8 y^5\)
D\(41,184 x^8 y^5\)

Our calculations confirm that \(329,472 x^5 y^8\) (Option b) and \(-41,184 x^8 y^5\) (Option c) are valid terms in the expansion of \((x - 2y)^{13}\). Since the question asks for a term in the expansion, both options b and c are correct. However, checking typical question formats, usually one answer is expected. Given both are valid, let us specify the correct ones as \(\boxed{\text{b and c}}\).

Examples

The binomial theorem is used in fields like probability and statistics to determine the distribution of independent events. For instance, if you are modeling the probability of flipping a coin or the growth of a business strategy with several independent variables, binomial expansions allow you to calculate the probability or impact of specific combinations of outcomes efficiently. This is a fundamental tool for engineers, economists, and data analysts to predict outcomes in complex systems.