What is the fifth term in the expansion of $(3 x-3 y)^7$ ?
To find the fifth term in the binomial expansion of \((3x - 3y)^7\), we apply the Binomial Theorem. The theorem states that \((a + b)^n = \sum_{k=0}^n \binom{n}{k} a^{n-k} b^k\), where \(\binom{n}{k}\) is the binomial coefficient given by \(\frac{n!}{k!(n-k)!}\). In our expression, we have \(a = 3x\), \(b = -3y\), and \(n = 7\). The terms are ordered such that the first term corresponds to \(k=0\), the second to \(k=1\), and so on. Therefore, the fifth term corresponds to \(k = 4\). The general formula for the \((k+1)\)-th term is \(T_{k+1} = \binom{n}{k} a^{n-k} b^k\). For \(k=4\), this is \(T_5 = \binom{7}{4} (3x)^{7-4} (-3y)^4\).
First, we calculate the binomial coefficient \(\binom{7}{4}\):
\[\binom{7}{4} = \frac{7!}{4!3!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35.\]
Next, we determine the powers of the individual terms:
\[(3x)^{7-4} = (3x)^3 = 3^3 x^3 = 27x^3.\]
\[(-3y)^4 = (-3)^4 y^4 = 81y^4.\]
Multiplying these components together, we get:
\[T_5 = 35 \times 27x^3 \times 81y^4.\]
Calculating the numerical coefficient:
\[35 \times 27 \times 81 = 35 \times 2187 = 76545.\]
Thus, the fifth term is \(76545x^3 y^4\).
Binomial expansion is widely used in probability and statistics, particularly in calculating binomial distributions which model the number of successes in a series of independent experiments. For instance, if you are calculating the likelihood of specific outcomes in a series of coin flips or quality control tests, the binomial theorem allows you to determine the coefficient of a specific event combination, like getting exactly 4 heads out of 7 tosses. This mathematical structure helps engineers and scientists predict and analyze systems involving discrete events and binomial probabilities.