- Break down the expression into two terms: \(4 \sqrt[3]{x^{10}}\) and \(5x^3 \sqrt[3]{8x}\).
- Simplify the first term: \(\sqrt[3]{x^{10}} = \sqrt[3]{x^9 \cdot x} = x^3 \sqrt[3]{x}\), so \(4 \sqrt[3]{x^{10}} = 4x^3 \sqrt[3]{x}\).
- Simplify the second term: \(\sqrt[3]{8x} = \sqrt[3]{8} \cdot \sqrt[3]{x} = 2 \sqrt[3]{x}\), so \(5x^3 \sqrt[3]{8x} = 5x^3 \cdot 2 \sqrt[3]{x} = 10x^3 \sqrt[3]{x}\).
- Sum the terms to obtain the simplest form: \(4x^3 \sqrt[3]{x} + 10x^3 \sqrt[3]{x} = \boxed{14x^3 \sqrt[3]{x}}\).
Explanation
- Problem Analysis and Initial Breakdown
To simplify the given expression \(4 \sqrt[3]{x^{10}} + 5x^3 \sqrt[3]{8x}\) where \(x
eq 0\), we begin by examining each term separately. We will use the properties of radicals and exponents, specifically that \(\sqrt[n]{a \cdot b} = \sqrt[n]{a} \cdot \sqrt[n]{b}\) and \(\sqrt[n]{a^n} = a\).
- Simplifying the First Term
Consider the first term: \(4 \sqrt[3]{x^{10}}\). We can rewrite \(x^{10}\) as \(x^9 \cdot x\). Since \(x^9 = (x^3)^3\), the cube root is \(x^3\). Thus,
\[\sqrt[3]{x^{10}} = \sqrt[3]{x^9 \cdot x} = \sqrt[3]{x^9} \cdot \sqrt[3]{x} = x^3 \sqrt[3]{x}.\]
Multiplying this by the coefficient 4, we get:
\[4 \sqrt[3]{x^{10}} = 4x^3 \sqrt[3]{x}.\]
- Simplifying the Second Term
Consider the second term: \(5x^3 \sqrt[3]{8x}\). We know that \(\sqrt[3]{8} = 2\). Applying the radical property, we have:
\[\sqrt[3]{8x} = \sqrt[3]{8} \cdot \sqrt[3]{x} = 2 \sqrt[3]{x}.\]
Substituting this back into the second term:
\[5x^3 \sqrt[3]{8x} = 5x^3 \cdot (2 \sqrt[3]{x}) = 10x^3 \sqrt[3]{x}.\]
- Combining Terms and Final Result
Finally, we combine the two simplified terms:
\[4x^3 \sqrt[3]{x} + 10x^3 \sqrt[3]{x}.\]
Since both terms contain the common factor \(x^3 \sqrt[3]{x}\), we can add their coefficients:
\[(4 + 10) x^3 \sqrt[3]{x} = 14x^3 \sqrt[3]{x}.\]
Thus, the expression in simplest form is \(\boxed{14x^3 \sqrt[3]{x}}\).
Examples
In many engineering and physics applications, you often encounter complex expressions involving radicals that represent physical dimensions or energy states. Simplifying these expressions is crucial for performing calculations efficiently and identifying relationships between different variables. For example, if an expression for volume is given by a formula involving cube roots of variable side lengths, simplifying it allows for easier calculation of the total volume as the variables change over time. Being able to combine like terms, as done here, is a fundamental skill for such tasks.