- Represent the function as \(y = 2x - 10\).
- Isolate \(x\) to get \(x = \frac{1}{2}y + 5\).
- Swap the variables to write the inverse function \(h(x) = \frac{1}{2}x + 5\).
- The final answer is \(\boxed{h(x) = \frac{1}{2}x + 5}\).
Explanation
- Setting up the Inverse Calculation
To find the inverse function \(h(x) = f^{-1}(x)\) of the given function \(f(x) = 2x - 10\), we begin by setting the function equal to \(y\):
\[y = 2x - 10.\]
In the inverse function, the roles of \(x\) and \(y\) are reversed. Therefore, we solve for \(x\) in terms of \(y\) to understand how to map the output back to the input.
- Solving for the Inverse Variable
Starting from the equation \(y = 2x - 10\), we add \(10\) to both sides to isolate the term containing \(x\):
\[y + 10 = 2x.\]
Next, we divide both sides by \(2\) to isolate \(x\):
\[x = \frac{y + 10}{2}.\]
This can be simplified by distributing the division:
\[x = \frac{y}{2} + \frac{10}{2} = \frac{1}{2}y + 5.\]
- Finalizing the Inverse Function
Now that we have solved for \(x\) in terms of \(y\), we express the inverse function \(h(x)\) by replacing \(y\) with \(x\):
\[h(x) = \frac{1}{2}x + 5.\]
Comparing this result to the provided options, we see that it matches the option \(h(x) = \frac{1}{2}x + 5\).
Examples
Finding the inverse of a function is crucial in various real-life applications, such as currency conversion. For example, if a function converts Dollars to Euros with a specific exchange rate and fee, the inverse function allows you to quickly calculate how many Dollars you need to obtain a target amount of Euros. Similarly, in programming or data processing, inverse functions are used to reverse operations like encryption/decryption or data scaling, ensuring that systems can return to their original states after transformation.