- Eliminate the fractions by multiplying the entire equation by the least common multiple of the denominators, which is 12.
- Simplify the resulting expression by expanding and combining like terms.
- Isolate the variable \(a\) by performing algebraic operations on both sides of the equation.
- Determine the final value of the variable, which is \(\boxed{5.25}\).
Explanation
- Analyzing the Equation and Finding a Common Denominator
To solve the linear equation \[\frac{2a - 5}{4} - \frac{1 - a}{3} = \frac{3a + 1}{6},\] we first identify the denominators 4, 3, and 6. To simplify the equation, we determine the least common multiple (LCM) of these denominators, which is 12. Multiplying every term in the equation by 12 will eliminate the fractions.
- Eliminating Fractions and Simplifying the Equation
Multiplying both sides of the equation by 12 yields:
\[12 \cdot \left(\frac{2a - 5}{4}\right) - 12 \cdot \left(\frac{1 - a}{3}\right) = 12 \cdot \left(\frac{3a + 1}{6}\right).\]
Simplifying each term gives:
\[3(2a - 5) - 4(1 - a) = 2(3a + 1).\]
Next, we expand the expressions:
\[6a - 15 - 4 + 4a = 6a + 2.\]
Combining like terms on the left side, we get:
\[10a - 19 = 6a + 2.\]
- Solving for a
Now, we isolate the variable \(a\). Subtracting \(6a\) from both sides:
\[4a - 19 = 2.\]
Adding 19 to both sides:
\[4a = 21.\]
Finally, dividing by 4:
\[a = \frac{21}{4} = 5.25.\]
Thus, the solution is \(a = 5.25\).
Examples
Linear equations like this are foundational for solving real-world problems involving rates and proportions. For example, imagine you are managing a project budget where costs are split across different departments based on fractional shares. If you need to determine the specific allocation amount represented by a variable that satisfies a budget balance equation, you use algebraic techniques just like this to find the exact value needed to maintain financial equality. Understanding these steps ensures you can solve for unknown variables in any proportional resource allocation scenario.