Review Seth's steps for rewriting and simplifying an expression.
Given: $\quad 8 x^6 \sqrt{200 x^{13}} \div 2 x^5 \sqrt{32 x^7}$
Step $1: = 8 x^6 \sqrt{4 \cdot 25 \cdot 2 \cdot\left(x^6\right)^2 \cdot x} \div 2 x^5 \sqrt{16 \cdot 2 \cdot\left(x^3\right)^2 \cdot x}$
Step $2: = 8 \cdot 2 \cdot 5 \cdot x^6 \cdot x^6 \sqrt{2 x} \div 2 \cdot 16 \cdot x^5 \cdot x^3 \sqrt{2 x}$
Step $3: = 80 x^{12} \sqrt{2 x} \div 32 x^8 \sqrt{2 x}$
Step $4: = \frac{80 x^{12} \sqrt{2 x}}{32 x^8 \sqrt{2 x}}$
Step $5: = \frac{5}{2} x^4$
Seth's first mistake was made in [Choose an answer], where he [Choose an answer].
Given: $\quad 8 x^6 \sqrt{200 x^{13}} \div 2 x^5 \sqrt{32 x^7}$
Step $1: = 8 x^6 \sqrt{4 \cdot 25 \cdot 2 \cdot\left(x^6\right)^2 \cdot x} \div 2 x^5 \sqrt{16 \cdot 2 \cdot\left(x^3\right)^2 \cdot x}$
Step $2: = 8 \cdot 2 \cdot 5 \cdot x^6 \cdot x^6 \sqrt{2 x} \div 2 \cdot 16 \cdot x^5 \cdot x^3 \sqrt{2 x}$
Step $3: = 80 x^{12} \sqrt{2 x} \div 32 x^8 \sqrt{2 x}$
Step $4: = \frac{80 x^{12} \sqrt{2 x}}{32 x^8 \sqrt{2 x}}$
Step $5: = \frac{5}{2} x^4$
Seth's first mistake was made in [Choose an answer], where he [Choose an answer].