Complete the statements below that show $y=x^2+2 x-1$ being converted to vertex form.



Form a perfect-square trinomial.

$y=x^2+2 x+\square-1-\square$

Verified Answer :

  • Identify the coefficient of the \(x\)-term, which is \(b=2\).
  • Calculate the constant needed to complete the square as \(\left(\frac{b}{2}\right)^2 = \left(\frac{2}{2}\right)^2 = 1\).
  • Substitute the value into the expression to get \(y = x^2 + 2x + 1 - 1 - 1\).
  • Factor the perfect square trinomial to obtain the vertex form: \(y = (x+1)^2 - 2\), meaning the missing value is \(\boxed{1}\).

Explanation

  1. Problem Analysis

We are given the quadratic function \(y = x^2 + 2x - 1\). The objective is to convert this into vertex form, which is written as \(y = a(x-h)^2 + k\), by completing the square. The problem specifically asks us to complete the expression \(y = x^2 + 2x + \square - 1 - \square\) to form a perfect-square trinomial. To do this, we need to determine the value that completes the square.

  1. Identifying the Value to Complete the Square

To complete the square for a quadratic expression of the form \(x^2 + bx\), we add and subtract the value \(\left(\frac{b}{2}\right)^2\). In our case, the coefficient of the \(x\)-term is \(b = 2\). Thus, we calculate:
\[\left(\frac{b}{2}\right)^2 = \left(\frac{2}{2}\right)^2 = 1^2 = 1.\]
This is the value that must be placed in the blank squares. Adding and subtracting the same value ensures that the original expression remains unchanged.

  1. Completing the Square and Final Form

Now, we substitute the value 1 into the expression:
\[y = x^2 + 2x + 1 - 1 - 1.\]
Next, we identify the perfect-square trinomial \(x^2 + 2x + 1\), which factors as \((x+1)^2\). Substituting this back into the equation, we get:
\[y = (x+1)^2 - 1 - 1.\]
Finally, simplifying the constant terms \(-1 - 1 = -2\), the vertex form of the equation is:
\[y = (x+1)^2 - 2.\]
The missing value to complete the square in the provided expression is 1.

Examples

Completing the square is a powerful tool in physics and engineering. For example, if you are modeling the trajectory of a ball thrown into the air, the path is often described by a quadratic equation. By converting this equation into vertex form, you can instantly identify the vertex \((h, k)\), which represents the maximum height (k) reached by the ball at a specific time (h). This helps in predicting the peak performance or optimal range in sports like basketball or projectile motion experiments.