- Rewrite the equation as \(z^3 - z^2 - 20z = 0\).
- Factor out \(z\) to obtain \(z(z^2 - z - 20) = 0\).
- Factor the quadratic \(z^2 - z - 20\) as \((z - 5)(z + 4)\).
- Identify the roots \(z = 0\), \(z = 5\), and \(z = -4\).
- The solution set is \(\boxed{0, 5, -4}\).
Explanation
- Standard Form of the Equation
To solve the equation \(z^3 - z^2 = 20z\), we first rewrite it in the standard form \(f(z) = 0\) by subtracting \(20z\) from both sides. This gives us:
\[z^3 - z^2 - 20z = 0\]
This is a cubic equation, and our goal is to find all values of \(z\) that satisfy this condition.
- Factoring out the Common Variable
We can observe that every term in the equation shares a common factor of \(z\). Factoring out \(z\) from the expression simplifies the equation:
\[z(z^2 - z - 20) = 0\]
This product is equal to zero if at least one of the factors is equal to zero. This implies two conditions:
- \(z = 0\)
- \(z^2 - z - 20 = 0\)
- Solving the Quadratic Equation
Now, we need to solve the quadratic equation \(z^2 - z - 20 = 0\). We look for two numbers that multiply to \(-20\) and add up to \(-1\). These numbers are \(-5\) and \(4\). Thus, we can factor the quadratic expression as follows:
\[(z - 5)(z + 4) = 0\]
Setting each factor to zero gives us the roots:
- \(z - 5 = 0 \implies z = 5\)
- \(z + 4 = 0 \implies z = -4\)
- Final Solutions
Combining the result from our first factor (\(z = 0\)) with the roots obtained from the quadratic equation (\(z = 5\) and \(z = -4\)), we conclude that the solutions for the equation are \(z = 0\), \(z = 5\), and \(z = -4\).
The final answer is \(\boxed{0, 5, -4}\).
Examples
Cubic equations often appear in geometry and physical problems. For example, if you are designing a box where the length, width, and height are related to a variable \(z\), the volume might be described by a cubic function. Solving an equation like this helps find dimensions that satisfy specific volume requirements, ensuring your structure meets the necessary specifications.