There are three different versions of the Pythagorean Identities. We will use $\sin^2(\theta) + \cos^2(\theta) = 1$ to obtain the other two versions.
AAssuming that $\cos(\theta)
eq 0$, divide both sides of the identity $\sin^2(\theta) + \cos^2(\theta) = 1$ by $\cos^2(\theta)$. What do we get?
BWrite the result from part (a) in the form: $(\dots)^2 + 1 = (\dots)^2$
CSimplify the expression in part (b) by recognizing the equivalent formulas for the terms inside the parentheses.
DAssuming that $\sin(\theta)
eq 0$, divide both sides of the identity $\sin^2(\theta) + \cos^2(\theta) = 1$ by $\sin^2(\theta)$. What do we get?
EWrite the result from part (d) in the form: $1 + (\dots)^2 = (\dots)^2$
(f) Simplify the expression in part (e) by recognizing the equivalent formulas for the terms inside the parentheses.
(g) Check your results in parts (c) and (f) with the formula sheet.
AAssuming that $\cos(\theta)
BWrite the result from part (a) in the form: $(\dots)^2 + 1 = (\dots)^2$
CSimplify the expression in part (b) by recognizing the equivalent formulas for the terms inside the parentheses.
DAssuming that $\sin(\theta)
EWrite the result from part (d) in the form: $1 + (\dots)^2 = (\dots)^2$
(f) Simplify the expression in part (e) by recognizing the equivalent formulas for the terms inside the parentheses.
(g) Check your results in parts (c) and (f) with the formula sheet.