- Simplify the given inequality \(6(y+1) < -x\) to the slope-intercept form \(y = -\frac{1}{6}x - 1\).
- Recognize that the strict inequality \(<\) indicates a dashed boundary line.
- Calculate two points on the boundary line, such as \((0, -1)\) and \((-6, 0)\).
- Determine the shaded region by testing the origin \((0,0)\), which results in a false statement, indicating the region below the dashed line is the solution set.
Explanation
- Analyzing the Inequality and Boundary Line
We are given the linear inequality \(6(y+1) < -x\). Our goal is to determine the nature of the boundary line, identify two points on this line, and determine the region that satisfies the inequality. The boundary line is defined by the equation \(6(y+1) = -x\). To simplify this, we can distribute the 6 on the left side:
\[6y + 6 = -x\]
Next, we isolate \(y\) to express the line in slope-intercept form \(y = mx + b\):
\[6y = -x - 6\]
\[y = -\frac{1}{6}x - 1\]
This form makes it easy to identify the slope \(m = -\frac{1}{6}\) and the y-intercept \(b = -1\).
- Determining the Boundary Line Type
The inequality given is \(6(y+1) < -x\), which is a strict inequality (using the less-than symbol \(<\)). Because the inequality is strict, the points exactly on the boundary line \(y = -\frac{1}{6}x - 1\) do not satisfy the condition. Therefore, the boundary line must be represented as a dashed line.
- Finding Two Points on the Boundary Line
To find two points on the boundary line \(y = -\frac{1}{6}x - 1\), we can choose two arbitrary values for \(x\) and calculate the corresponding \(y\) values.
- Let \(x = 0\):
\[y = -\frac{1}{6}(0) - 1 = -1\]
So, one point on the line is \((0, -1)\).
- Let \(x = -6\):
\[y = -\frac{1}{6}(-6) - 1 = 1 - 1 = 0\]
So, another point on the line is \((-6, 0)\).
- Determining the Shaded Region
To determine which side of the boundary line satisfies the inequality \(6(y+1) < -x\), we test a point that is not on the line. The simplest point to test is the origin \((0, 0)\).
Substituting \((0, 0)\) into the inequality:
\[6(0+1) < -(0)\]
\[6(1) < 0\]
\[6 < 0\]
This statement is false. Since the origin does not satisfy the inequality, the solution region is the half-plane that does not contain the origin. Given the line \(y = -\frac{1}{6}x - 1\), the inequality \(y < -\frac{1}{6}x - 1\) represents the region below the line. Thus, the region to be shaded is the one below the dashed line.
Examples
Linear inequalities are widely used in resource allocation and optimization. For example, a budget constraint can be modeled as a linear inequality, such as \(10x + 5y \leq 100\), where \(x\) and \(y\) are quantities of two items. By graphing the inequality and identifying the shaded region (the feasible region), a business owner can visualize all combinations of goods they can afford to purchase while remaining within their budget. Understanding which side of a boundary line to shade is essential for finding the valid solutions to such practical problems.