NaF MgO
Boiling Point (°C)1695 3600
$N a ^{ + }$ $Mg ^{2+}$ $F ^{-}$ $Cl ^{-}$ $O ^{2-}$
Ionic Radius (pm)76 72 133 181 140
Based on the data in the tables above, which of the following statements provides the best prediction for the boiling point of NaCl?
ANaCl will have a lower boiling point than NaF because the coulombic attractions are weaker in NaCl than in NaF.
BNaCl will have a boiling point between that of NaF and MgO because the covalent character of the bonds in NaCl is intermediate between that of MgO and NaF.
CNaCl will have a higher boiling point than MgO because the ions are spaced farther apart in NaCl.
DNaCl will have a higher boiling point than MgO because the energy required to transfer electrons from the anion to the cation is larger in NaCl than in MgO.
| NaF | MgO | |
Boiling Point (°C) | 1695 | 3600 |
| $N a ^{ + }$ | $Mg ^{2+}$ | $F ^{-}$ | $Cl ^{-}$ | $O ^{2-}$ | |
Ionic Radius (pm) | 76 | 72 | 133 | 181 | 140 |
ANaCl will have a lower boiling point than NaF because the coulombic attractions are weaker in NaCl than in NaF.
BNaCl will have a boiling point between that of NaF and MgO because the covalent character of the bonds in NaCl is intermediate between that of MgO and NaF.
CNaCl will have a higher boiling point than MgO because the ions are spaced farther apart in NaCl.
DNaCl will have a higher boiling point than MgO because the energy required to transfer electrons from the anion to the cation is larger in NaCl than in MgO.