- Expand the terms on both sides of the inequality: \(8x - 6 \geq -4x\).
- Collect the variable terms on the left: \(12x \geq 6\).
- Solve for \(x\) by dividing by 12: \(x \geq 0.5\).
- The solution set is \(\boxed{x \geq 0.5}\).
Explanation
- Analyzing the Inequality
We are given the linear inequality:
\[2(4x - 3) \geq -3(3x) + 5x\]
Our objective is to solve for \(x\) and find which of the provided options matches the solution set. We observe that this involves algebraic manipulation of a linear inequality. We will expand, simplify, and isolate the variable \(x\).
- Expanding and Simplifying the Inequality
First, we expand the expressions on both sides of the inequality:
- The left side: \(2(4x - 3) = 8x - 6\).
- The right side: \(-3(3x) + 5x = -9x + 5x = -4x\).
Now, substitute these back into the original inequality:
\[8x - 6 \geq -4x\]
- Solving for x
Next, we isolate the variable \(x\) on one side of the inequality. We add \(4x\) to both sides:
\[8x + 4x - 6 \geq -4x + 4x\]
\[12x - 6 \geq 0\]
Then, add 6 to both sides:
\[12x \geq 6\]
Finally, divide both sides by 12:
\[x \geq \frac{6}{12}\]
\[x \geq 0.5\]
- Conclusion
Comparing our derived solution \(x \geq 0.5\) with the given options:
- \(x \geq 0.5\)
- \(x \geq 2\)
- \((-\infty, 0.5]\)
- \((-\infty, 2]\)
The solution matches the first option. Thus, the solution to the inequality is \(x \geq 0.5\).
Examples
Linear inequalities are essential in real-life optimization problems. Imagine you are running a business and need to make a profit. Suppose your revenue function is \(R(x) = 8x\) and your cost function is \(C(x) = 6 - 4x\). To find the minimum production level \(x\) needed to ensure that revenue is at least equal to costs, you would set up the inequality \(8x \geq 6 - 4x\), which is exactly the type of problem we just solved. Understanding how to solve these inequalities helps in making informed decisions about production targets, budget management, and resource allocation.