Kate begins solving the equation $\frac{2}{3}(6 x-3)=\frac{1}{2}(6 x-4)$. Her work is correct and is shown below.
$\begin{aligned}
\frac{2}{3}(6 x-3) & =\frac{1}{2}(6 x-4) \\
4 x-2 & =3 x-2
\end{aligned}$
When she adds 2 to both sides, the equation $4 x=3 x$ results. Which statement best describes what happens to $x$?
AThe equation has infinite solutions.
BThe equation has one solution: $x=0$.
CThe equation has one solution: $x=\frac{4}{3}$.
DThe equation has no solution.
$\begin{aligned}
\frac{2}{3}(6 x-3) & =\frac{1}{2}(6 x-4) \\
4 x-2 & =3 x-2
\end{aligned}$
When she adds 2 to both sides, the equation $4 x=3 x$ results. Which statement best describes what happens to $x$?
AThe equation has infinite solutions.
BThe equation has one solution: $x=0$.
CThe equation has one solution: $x=\frac{4}{3}$.
DThe equation has no solution.