Verified Answer :

  • \(C_{12}H_{22}O_{11}\) is an organic compound.
  • \(Mg(OH)_2\) is an ionic compound.
  • \(H_2O\) is a covalent compound.
  • \(Cu_3Zn_2\) is a metallic compound (alloy).
  • \(Au\) is a chemical element.

Explanation

  1. Analysis and Classification of Chemical Formulas

To determine the compound type for each formula, we analyze the atomic composition and bonding characteristics of each substance.

  1. \(C_{12}H_{22}O_{11}\): This formula represents a carbohydrate (such as sucrose). Because it consists primarily of carbon and hydrogen atoms bonded covalently with oxygen, it is classified as an organic compound.
  2. \(Mg(OH)_2\): This substance consists of a magnesium cation (\(Mg^{2+}\)) and two hydroxide anions (\(OH^{-}\)). The strong electrostatic attraction between these oppositely charged ions characterizes it as an ionic compound.
  3. \(H_2O\): This molecule is formed by hydrogen atoms sharing electrons with an oxygen atom. Since it is formed by sharing electrons between non-metal atoms, it is classified as a covalent (or molecular) compound.
  4. \(Cu_3Zn_2\): This substance is formed by combining two transition metals, copper (Cu) and zinc (Zn). A mixture or combination of metallic elements is characterized as a metallic compound or an alloy.
  5. \(Au\): This symbol represents gold, which consists only of gold atoms. Since it is composed of only one type of atom and cannot be broken down by chemical means, it is a chemical element.

Examples

Chemical classification is foundational in fields like material science and pharmacy. For example, identifying if a medicine is an organic compound can determine its solubility in the body, while recognizing a substance like an alloy (similar to \(Cu_3Zn_2\)) helps engineers choose materials for strength and conductivity in electronics. Understanding these distinctions allows scientists to predict how substances will behave in various environments and chemical reactions.