Describe the mistake this student made when solving the compound inequality:
$-4 \leq-10-2 x<6$
$\begin{array}{l}
-4 \leq-10-2 x<6 \\
+10+10
\end{array}$
$\begin{array}{l}
\underset{-2}{6} \leq-2 x<16 \\
\div-2<-2 \\
4 \leq x<-8
\end{array}$
AThey divided by a negative number and didn't flip the symbols, and 6 divided by -2 equals -3, not 4.
BThey divided by -2 from all parts and should have divided by 2, and 6 divided by 2 equals 3, not 4.
CThere is no mistake, the student is correct.
DThey added 10 to all parts and should have subtracted.
$-4 \leq-10-2 x<6$
$\begin{array}{l}
-4 \leq-10-2 x<6 \\
+10+10
\end{array}$
$\begin{array}{l}
\underset{-2}{6} \leq-2 x<16 \\
\div-2<-2 \\
4 \leq x<-8
\end{array}$
AThey divided by a negative number and didn't flip the symbols, and 6 divided by -2 equals -3, not 4.
BThey divided by -2 from all parts and should have divided by 2, and 6 divided by 2 equals 3, not 4.
CThere is no mistake, the student is correct.
DThey added 10 to all parts and should have subtracted.