$\begin{array}{l}\frac{7}{4}-\frac{1}{2}=\frac{7-2}{5} \\ -\frac{5}{3}-\frac{4}{5} \frac{25-12}{15}=\frac{13}{15} \\ -\frac{3}{4}-\frac{1}{4}=\frac{3-1}{4}=\frac{2}{4}=1 \\ \frac{5}{4}-\frac{3}{8} \frac{18-3=15}{8} \\ \text { a, } \frac{2}{3}-\frac{1}{3} \frac{2-1=1}{3} \\ 6, \frac{1}{2}-\frac{1}{3} \\ \text { s } \frac{2}{3}-\frac{1}{2}\end{array}$

Verified Answer :

  • Find a common denominator for the two fractions in each expression, which is 6.
  • Convert the fractions to equivalent forms: for 'b.', \(\frac{1}{2} = \frac{3}{6}\) and \(\frac{1}{3} = \frac{2}{6}\); for 'c.', \(\frac{2}{3} = \frac{4}{6}\) and \(\frac{1}{2} = \frac{3}{6}\).
  • Subtract the numerators: \(\frac{3-2}{6} = \frac{1}{6}\) and \(\frac{4-3}{6} = \frac{1}{6}\).
  • Final answers: \(\text{b. } \boxed{\frac{1}{6}}, \text{c. } \boxed{\frac{1}{6}}\).

Explanation

  1. Analysis of the problem

The task requires computing the result of two fraction subtraction expressions: \(\frac{1}{2} - \frac{1}{3}\) (label 'b.') and \(\frac{2}{3} - \frac{1}{2}\) (label 'c.'). To subtract fractions with different denominators, we find a common denominator, convert each fraction to an equivalent form with this common denominator, and then subtract the numerators while keeping the common denominator constant.

  1. Solving expression 'b.'

To solve \(\frac{1}{2} - \frac{1}{3}\), we first determine a common denominator for 2 and 3, which is 6. Converting the fractions:
\(\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}\)
\(\frac{1}{3} = \frac{1 \times 2}{3 \times 2} = \frac{2}{6}\)
Subtracting these:
\(\frac{3}{6} - \frac{2}{6} = \frac{3 - 2}{6} = \frac{1}{6}\)
Thus, the result for 'b.' is \(\frac{1}{6}\).

  1. Solving expression 'c.'

To solve \(\frac{2}{3} - \frac{1}{2}\), we find a common denominator for 3 and 2, which is 6. Converting the fractions:
\(\frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6}\)
\(\frac{1}{2} = \frac{1 \times 3}{2 \times 3} = \frac{3}{6}\)
Subtracting these:
\(\frac{4}{6} - \frac{3}{6} = \frac{4 - 3}{6} = \frac{1}{6}\)
Thus, the result for 'c.' is \(\frac{1}{6}\).

Examples

Fractions are used in everyday life for tasks like cooking and measurement. For example, if a recipe calls for \(\frac{2}{3}\) of a cup of flour and you already used \(\frac{1}{2}\) of a cup, you can calculate the remaining amount needed by performing the subtraction \(\frac{2}{3} - \frac{1}{2} = \frac{1}{6}\) of a cup. This simple application helps ensure recipes are followed accurately and resources are measured correctly.