The main cable of a suspension bridge is modeled by the equation $y=0.0048(x-50)^2+6$. At what horizontal distances from the left support is the cable 10 ft above the roadway?
$y=$ height in feet of cable above the roadway
$x=$ horizontal distance in feet from left support
Choose the equation one must solve to answer the question:
A$0=0.0048(x-50)^2+6$
B$y=0.0048(10-50)^2+6$
C$10=0.0048(x-50)^2+6$
$y=$ height in feet of cable above the roadway
$x=$ horizontal distance in feet from left support
Choose the equation one must solve to answer the question:
A$0=0.0048(x-50)^2+6$
B$y=0.0048(10-50)^2+6$
C$10=0.0048(x-50)^2+6$