Answered

Given the function $C(r)=3 r^4+12 r^3-36 r^2$:



Its $C$-intercept is □

Its $r$-intercepts are □

Verified Answer :

  • Evaluate the function at \(r=0\) to find the C-intercept: \(C(0) = 0\).
  • Set the polynomial equal to zero to find the r-intercepts: \(3r^4 + 12r^3 - 36r^2 = 0\).
  • Factor out the common term \(3r^2\) to get \(3r^2(r^2 + 4r - 12) = 0\).
  • Solve the quadratic factor \((r+6)(r-2) = 0\) to find the roots \(r = -6, 0, 2\).
  • The final answers are: C-intercept \(\boxed{0}\) and r-intercepts \(\boxed{-6, 0, 2}\).

Explanation

  1. Finding the C-intercept

To find the C-intercept of the function \(C(r) = 3r^4 + 12r^3 - 36r^2\), we evaluate the function at \(r = 0\). Substituting \(r = 0\) into the expression, we get \(C(0) = 3(0)^4 + 12(0)^3 - 36(0)^2 = 0\). Therefore, the C-intercept is 0.

  1. Finding the r-intercepts

To find the r-intercepts, we set \(C(r) = 0\) and solve for \(r\):
\[3r^4 + 12r^3 - 36r^2 = 0\]
We can factor out the common term \(3r^2\):
\[3r^2(r^2 + 4r - 12) = 0\]
This gives us two main components to solve:

  1. \(3r^2 = 0\), which implies \(r = 0\).
  2. \(r^2 + 4r - 12 = 0\).

To solve the quadratic equation \(r^2 + 4r - 12 = 0\), we look for two numbers that multiply to -12 and add to 4. These numbers are 6 and -2. Thus, the equation factors as:
\[(r + 6)(r - 2) = 0\]
This gives us the roots \(r = -6\) and \(r = 2\). Combining all these, the r-intercepts are \(-6, 0,\) and \(2\).

  1. Conclusion

We have determined that the C-intercept is 0 and the r-intercepts are \(-6\), \(0\), and \(2\). Thus, the C-intercept is \(\boxed{0}\) and the r-intercepts are \(\boxed{-6, 0, 2}\).

Examples

In physics, modeling the trajectory or energy output of a system often involves finding intercepts to identify critical points (like when a projectile hits the ground or when energy levels change). For example, if a machine's energy efficiency is modeled by \(E(t) = 3t^4 + 12t^3 - 36t^2\), finding the time intercepts (r-intercepts) would help determine the specific moments when the net energy output is zero, which is crucial for analyzing energy cycles or system operation windows.