- Express the radicands 32 and 512 as powers of 2: \(32 = 2^4 \cdot 2\) and \(512 = 2^8 \cdot 2\).
- Simplify each radical: \(\sqrt[4]{32} = 2\sqrt[4]{2}\) and \(\sqrt[4]{512} = 4\sqrt[4]{2}\).
- Substitute these back: \(-2\sqrt[4]{2} + 2(4\sqrt[4]{2}) = -2\sqrt[4]{2} + 8\sqrt[4]{2}\).
- Combine terms to reach the final answer: \(\boxed{6\sqrt[4]{2}}\).
Explanation
- Analyzing the Radicands
We are asked to simplify the expression \(-\sqrt[4]{32} + 2\sqrt[4]{512}\). To simplify radical expressions of this form, we express the radicands as powers of their prime factors and extract any perfect fourth powers. Here, the base is 2, since both 32 and 512 are powers of 2. Specifically, \(32 = 2^5\) and \(512 = 2^9\).
- Simplifying Each Radical Term
We can rewrite the radicands as follows:
\[ 32 = 2^4 \cdot 2^1 \]
\[ 512 = 2^8 \cdot 2^1 \]
Using the property \(\sqrt[4]{a \cdot b} = \sqrt[4]{a} \cdot \sqrt[4]{b}\), we can simplify the radicals:
\[ \sqrt[4]{32} = \sqrt[4]{2^4 \cdot 2} = \sqrt[4]{2^4} \cdot \sqrt[4]{2} = 2 \cdot \sqrt[4]{2} \]
\[ \sqrt[4]{512} = \sqrt[4]{2^8 \cdot 2} = \sqrt[4]{(2^2)^4 \cdot 2} = 2^2 \cdot \sqrt[4]{2} = 4 \cdot \sqrt[4]{2} \]
- Final Calculation and Conclusion
Now, substitute these simplified forms back into the original expression:
\[ -\sqrt[4]{32} + 2\sqrt[4]{512} = -(2 \cdot \sqrt[4]{2}) + 2 \cdot (4 \cdot \sqrt[4]{2}) \]
Perform the multiplication for the second term:
\[ -(2 \cdot \sqrt[4]{2}) + 8 \cdot \sqrt[4]{2} \]
Now, combine the like terms by factoring out \(\sqrt[4]{2}\):
\[ (-2 + 8) \cdot \sqrt[4]{2} = 6 \cdot \sqrt[4]{2} \]
The final simplified expression is \(6\sqrt[4]{2}\).
Examples
In manufacturing or engineering, understanding how to simplify radicals is useful when dealing with scales or dimensions that involve roots of area or volume. For instance, if you have a square-shaped component with an area of 32 square centimeters, its side length is \(\sqrt{32}\) cm. If you need to manipulate these dimensions to fit specific requirements, simplifying the radical forms allows for easier comparisons and calculations. Recognizing that \(\sqrt[4]{32} = 2\sqrt[4]{2}\) helps in standardizing these measurements, just as we simplified the expression in this problem.