- The vertex form of a quadratic function is \(y = a(x - h)^2 + k\), where \((h, k)\) is the vertex.
- Comparing \(y = 2(x + 5)^2 - 4\) to the vertex form, we identify \(h = -5\) and \(k = -4\).
- The vertex of the parabola is \((-5, -4)\).
- Final Answer: \(\boxed{(-5, -4)}\).
Explanation
- Analyzing the Quadratic Function in Vertex Form
The given function is \(y = 2(x + 5)^2 - 4\). This is a quadratic function expressed in vertex form. The vertex form of a parabola is defined by the equation \(y = a(x - h)^2 + k\), where \((h, k)\) represents the coordinates of the vertex of the parabola. Identifying the vertex allows us to understand the peak or the turning point of the parabolic curve.
- Determining the Vertex Coordinates
To identify the vertex \((h, k)\), we compare the provided equation \(y = 2(x + 5)^2 - 4\) to the general vertex form equation \(y = a(x - h)^2 + k\).
- The coefficient \(a\) is 2, which determines the vertical stretch of the parabola.
- By matching the term \((x + 5)\) with \((x - h)\), we can see that \(x - h = x + 5\), which implies that \(-h = 5\), and therefore \(h = -5\).
- By matching the constant term, we have \(k = -4\).
Thus, the coordinates of the vertex are \((h, k) = (-5, -4)\).
- Final Result and Conclusion
We have identified that the vertex \((h, k)\) of the parabola \(y = 2(x + 5)^2 - 4\) is \((-5, -4)\). This vertex is the lowest point on the parabola since the coefficient of the squared term is positive, indicating that the parabola opens upwards. The final coordinates are \(\boxed{(-5, -4)}\).
Examples
In real-world applications, parabolas often describe the trajectory of objects thrown into the air, such as a basketball shot or a kicked ball. The vertex of such a parabola represents the highest point that the object reaches during its flight. By identifying the vertex of the function that models a path, engineers and athletes can determine the maximum height or depth of a specific design, ensuring safety, accuracy, or optimal performance in sports and architecture.