What is $x^2+6x=x^2-6x$ as a system?


A$\begin{array}{l}

y=-x^2-6x \\

y=x^2-6x

\end{array}$


B$\begin{array}{l}

y=-x^2+6x \\

y=x^2-6x

\end{array}$


C$\begin{array}{l}

y=x^2+6x \\

y=x^2-6x

\end{array}$

Verified Answer :

  • Identify the equation as a pair of functions \(f(x) = x^2 + 6x\) and \(g(x) = x^2 - 6x\).
  • Translate the equality \(f(x) = g(x)\) into a system of two equations by setting \(y\) equal to each side: \(y = f(x)\) and \(y = g(x)\).
  • Recognize that the resulting system \(y = x^2 + 6x\) and \(y = x^2 - 6x\) matches choice (c).
  • The final answer is \(\boxed{\text{c}}\).

Explanation

  1. Understanding the Representation of an Equation as a System

To represent an equation of the form \(f(x) = g(x)\) as a system of equations, we look for two equations that involve a variable \(y\), such that substituting \(y\) leads back to the original equation. We can set \(y\) equal to each side of the equation:
\[y = f(x)\]
\[y = g(x)\]
By setting these two equations equal to each other (\(f(x) = g(x)\)), we find the points of intersection for the two graphs, which corresponds exactly to the solutions for \(x\) in the original equation.

  1. Applying the Concept to the Given Equation

Given the equation \(x^2 + 6x = x^2 - 6x\), we can identify the two functions on each side:
\[f(x) = x^2 + 6x\]
\[g(x) = x^2 - 6x\]
To create a system of equations that reflects this equality, we set \(y\) equal to each expression:
\[y = x^2 + 6x\]
\[y = x^2 - 6x\]
This system represents the intersection of the two parabolas \(y = x^2 + 6x\) and \(y = x^2 - 6x\). Any point \((x, y)\) that satisfies both equations must have the same \(y\)-coordinate, meaning \(x^2 + 6x = x^2 - 6x\).

  1. Selecting the Correct System

We compare our derived system:
\[\begin{array}{l} y = x^2 + 6x \ y = x^2 - 6x \end{array}\]
with the provided choices:

A\(\begin{array}{l} y = -x^2 - 6x \ y = x^2 - 6x \end{array}\)
B\(\begin{array}{l} y = -x^2 + 6x \ y = x^2 - 6x \end{array}\)
C\(\begin{array}{l} y = x^2 + 6x \ y = x^2 - 6x \end{array}\)

Choice (c) matches our derived system exactly. Therefore, the correct representation of the equation as a system is choice (c).

Examples

In data science and economics, finding the equilibrium point between supply and demand is a classic application of this method. For example, if a demand function is \(D(p) = 100 - 2p^2\) and a supply function is \(S(p) = p^2 + 10\), the equilibrium price occurs where \(D(p) = S(p)\), which can be visualized as the intersection of the systems \(y = 100 - 2p^2\) and \(y = p^2 + 10\). Solving this system helps businesses and researchers determine the optimal price at which supply matches demand.