In 2015, Macon County had a population of 53,792. The population increases by 2.5\% annually.



Which function can be used to model the population $t$ years after 2015?


A$f(t)=53,792(1.25)^t$
B$f(t)=53,792(1.025)^t$
C$f(t)=1.25 t+53,792$
D$f(t)=1.025 t+53,792$

Verified Answer :

  • Identify the initial population \(P_0 = 53,792\) and the growth rate \(r = 0.025\).
  • Recognize that constant annual percentage growth follows the exponential function \(f(t) = P_0(1 + r)^t\).
  • Substitute the values into the formula to obtain \(f(t) = 53,792(1.025)^t\).
  • Select the matching function: \(\boxed{f(t) = 53,792(1.025)^t}\).

Explanation

  1. Analysis of the Growth Model

The problem asks us to model the population growth of Macon County after the year 2015. We are given the initial population in 2015, \(P_0 = 53,792\), and the constant annual growth rate, \(r = 2.5\%\). Let \(t\) represent the number of years after 2015. Since the population grows by a fixed percentage each year, this is a classic case of exponential growth. The standard form for an exponential growth function is \(f(t) = P_0(1 + r)^t\), where \(P_0\) is the initial amount, \(r\) is the growth rate expressed as a decimal, and \(t\) is the time elapsed.

  1. Formulating the Function

First, we convert the annual growth rate from a percentage to a decimal:
\[r = 2.5\% = \frac{2.5}{100} = 0.025.\]
Next, we determine the growth factor, which is the base of our exponent in the model:
\[1 + r = 1 + 0.025 = 1.025.\]
Now, we substitute the initial population \(P_0 = 53,792\) and the growth factor \(1.025\) into the general exponential growth formula \(f(t) = P_0(1 + r)^t\). This gives us the function:
\[f(t) = 53,792(1.025)^t.\]

  1. Conclusion and Selection

We compare our derived function \(f(t) = 53,792(1.025)^t\) with the given choices:

  • \(f(t) = 53,792(1.25)^t\)
  • \(f(t) = 53,792(1.025)^t\)
  • \(f(t) = 1.25t + 53,792\)
  • \(f(t) = 1.025t + 53,792\)

Our derived function matches the second option. Thus, the correct function to model the population \(t\) years after 2015 is \(f(t) = 53,792(1.025)^t\), and the correct choice is \(\boxed{f(t) = 53,792(1.025)^t}\).

Examples

Exponential growth models like this one are essential in real-world scenarios beyond population studies. For example, if you invest \(\$1,000\) in a savings account that earns a constant annual compound interest rate of \(3\%\), the balance of your account after \(t\) years can be modeled using the same structure: \(B(t) = 1000(1 + 0.03)^t = 1000(1.03)^t\). Understanding these models helps individuals make informed financial decisions and allows organizations to project future trends accurately based on current data.