The points $(0,1)$ and $(1,4)$ are contained in the graph of the equation with only two variables, $x$ and $y$. Select all of the true statements.
We are given two points, \((0, 1)\) and \((1, 4)\), and we need to determine which statements are true regarding equations of the forms \(y = a(b)^x\) and \(y = mx + c\) that pass through these points.
First, let's analyze the exponential form \(y = a(b)^x\).
Substituting the point \((0, 1)\):
\[1 = a(b)^0 = a(1) = a\]
So, \(a = 1\).
Substituting the point \((1, 4)\):
\[4 = a(b)^1 = 1(b) = b\]
So, \(b = 4\).
The unique equation is \(y = 1(4)^x = 4^x\). Therefore, there is exactly one equation of the form \(y = a(b)^x\) passing through these points.
Next, let's analyze the linear form \(y = mx + b\) (we will use \(c\) as the intercept to distinguish it from the \(b\) in the exponential form: \(y = mx + c\)).
Substituting the point \((0, 1)\):
\[1 = m(0) + c \implies c = 1\]
Substituting the point \((1, 4)\):
\[4 = m(1) + 1 \implies m + 1 = 4 \implies m = 3\]
The unique equation is \(y = 3x + 1\). Therefore, there is exactly one equation of the form \(y = mx + b\) passing through these points.
Based on our analysis:
This problem illustrates how two distinct points uniquely define both a linear relationship and an exponential relationship. In real-world applications, this is fundamental to data fitting. For instance, if you track the growth of a bank balance over two months, you can use these mathematical models to predict future values. A linear model might represent simple interest, while an exponential model represents compound interest, helping you understand how different growth rates affect your savings over time.