Verified Answer :

  • The equation \(\tan x = 0\) implies \(\sin x = 0\) provided \(\cos x eq 0\).
  • Within the interval \([0, 2\pi)\), the solutions for \(\sin x = 0\) are \(x = 0\) and \(x = \pi\).
  • The general solution for \(\tan x = 0\) encompasses all integer multiples of \(\pi\).
  • The final set of solutions is expressed as \(\boxed{n\pi}\) for any integer \(n\).

Explanation

  1. Analyzing the Problem and Definitions

We are tasked with solving the trigonometric equation \(\tan x = 0\). The tangent function is defined as the ratio of sine to cosine: \(\tan x = \frac{\sin x}{\cos x}\). For the expression to be defined, we must have \(\cos x eq 0\). This means \(x eq \frac{\pi}{2} + k\pi\) for any integer \(k\). Given the definition, \(\tan x = 0\) is equivalent to \(\sin x = 0\) subject to the condition \(\cos x eq 0\).

  1. Solving for \(\sin x = 0\) within \([0, 2\pi)\)

We look for values of \(x\) such that \(\sin x = 0\). Within the interval \([0, 2\pi)\), the sine function is equal to zero at \(x = 0\) and \(x = \pi\). We verify the domain condition \(\cos x eq 0\) for these solutions:

  • At \(x = 0\), \(\cos 0 = 1 eq 0\).
  • At \(x = \pi\), \(\cos \pi = -1 eq 0\).

Both solutions \(x = 0\) and \(x = \pi\) are valid.

  1. Generalizing the Solutions

The solutions we found in the range \([0, 2\pi)\) are \(0\) and \(\pi\). The question asks for the solutions in the form \(a + n\pi\), where \(a \in [0, 2\pi)\).

  • For \(a = 0\), the solutions are \(0 + n\pi = n\pi\).
  • For \(a = \pi\), the solutions are \(\pi + n\pi\).

Notice that both sets describe the same set of points on the number line. Any integer multiple of \(\pi\) (i.e., \(\dots, -2\pi, -\pi, 0, \pi, 2\pi, \dots\)) satisfies \(\tan x = 0\). We can represent these solutions using \(a=0\) and \(n\) as any integer, yielding \(x = n\pi\).

Examples

The equation \(\tan x = 0\) often appears in wave mechanics and signal processing when determining the nodes of a standing wave. For instance, if a string is fixed at both ends, the points where the wave displacement is zero are related to the zeros of the sine or tangent functions. Understanding that \(\tan x = 0\) occurs at integer multiples of \(\pi\) helps in calculating the resonance frequencies and nodes of such physical systems.