- Identify the linear function \(g(x) = -4x - 1\).
- Solve for unknown \(x\) by rearranging the equation for given \(g(x)\): \(7 = -4x - 1 \implies x = -2\) and \(-13 = -4x - 1 \implies x = 3\).
- Evaluate unknown \(g(x)\) by substituting the given \(x\): \(g(0) = -4(0) - 1 = -1\) and \(g(-1) = -4(-1) - 1 = 3\).
- Completed pairs are \((-2, 7)\), \((0, -1)\), \((3, -13)\), and \((-1, 3)\).
- Final Answer: \(\boxed{-2, -1, 3, 3}\)
Explanation
- Analyzing the Problem
The problem asks us to complete a table of inputs and outputs for the linear function \(g(x) = -4x - 1\). This function maps an input \(x\) to an output \(g(x)\) by multiplying the input by \(-4\) and then subtracting \(1\). To find the missing values, we will evaluate the function for given inputs or solve for \(x\) when the output \(g(x)\) is provided.
- Solving for Inputs \(x\) Given Outputs \(g(x)\)
We first address the rows where the output \(g(x)\) is given, requiring us to solve for the input \(x\):
- For \(g(x) = 7\): We set up the equation \(7 = -4x - 1\). Adding \(1\) to both sides gives \(8 = -4x\). Dividing both sides by \(-4\) yields \(x = -2\).
- For \(g(x) = -13\): We set up the equation \(-13 = -4x - 1\). Adding \(1\) to both sides gives \(-12 = -4x\). Dividing both sides by \(-4\) yields \(x = 3\).
- Evaluating Outputs \(g(x)\) Given Inputs \(x\)
Next, we address the rows where the input \(x\) is given, requiring us to evaluate the function for the corresponding output \(g(x)\):
- For \(x = 0\): We substitute \(x=0\) into the function to get \(g(0) = -4(0) - 1 = 0 - 1 = -1\).
- For \(x = -1\): We substitute \(x=-1\) into the function to get \(g(-1) = -4(-1) - 1 = 4 - 1 = 3\).
- Conclusion and Final Table Values
Combining these results, the completed table is as follows:
- When \(g(x) = 7\), \(x = -2\).
- When \(x = 0\), \(g(x) = -1\).
- When \(g(x) = -13\), \(x = 3\).
- When \(x = -1\), \(g(x) = 3\).
Thus, the completed table entries are \(-2\), \(-1\), \(3\), and \(3\) respectively. The final table values correspond to \(x = \boxed{-2, 3}\) and \(g(x) = \boxed{-1, 3}\).
Examples
Linear functions are foundational for modeling real-world relationships where one variable changes at a constant rate relative to another. For example, if you are filling a water tank, the function \(V(t) = 5t + 10\) could represent the volume of water \(V\) in liters at time \(t\) in minutes, where the tank starts with 10 liters and fills at a constant rate of 5 liters per minute. By calculating inputs and outputs, you can determine how much water is in the tank at any given time or calculate the exact time needed to reach a desired volume.