Find the value of the expression.

$\begin{aligned}

x^2+20 y^3 & =9^2+20(2)^3 \\

& =\quad ?

\end{aligned}$

Verified Answer :

  • Evaluate the exponents: \(9^2 = 81\) and \(2^3 = 8\).
  • Multiply the result of the cube by 20: \(20 \times 8 = 160\).
  • Add the evaluated terms together: \(81 + 160 = 241\).
  • The final result is \(\boxed{241}\).

Explanation

  1. Analysis of the Expression

We are tasked to evaluate the mathematical expression \(x^2 + 20y^3 = 9^2 + 20(2)^3\). To solve this, we must follow the order of operations, often referred to by the acronym PEMDAS (Parentheses, Exponents, Multiplication/Division, Addition/Subtraction). First, we evaluate the exponent terms. The expression consists of a squared term \(9^2\) and a cubed term \(2^3\). Once these powers are evaluated, we perform the necessary multiplication and finally the addition to find the total value.

  1. Evaluating Exponents

First, we calculate the exponentiated values:

  • For the squared term: \(9^2 = 9 \times 9 = 81\).
  • For the cubed term: \(2^3 = 2 \times 2 \times 2 = 8\).

Now, substitute these back into the expression:
\(81 + 20(8)\).

  1. Multiplication and Addition

Following the order of operations, we next perform the multiplication:
\(20 \times 8 = 160\).
Now, the expression simplifies to the sum of the previously calculated values:
\(81 + 160\).

  1. Final Calculation and Conclusion

Finally, we perform the addition to find the result:
\(81 + 160 = 241\).
Thus, the value of the expression is \(\boxed{241}\).

Examples

This type of multi-step arithmetic is fundamental in science and engineering. For example, in physics, the kinetic energy of an object is proportional to the square of its velocity, \(E = \frac{1}{2}mv^2\). Similarly, when modeling population growth or financial compound interest, terms are often raised to a power (e.g., \(P(1+r)^n\)). Mastering the order of operations ensures that such calculations are performed accurately, preventing errors that could lead to incorrect predictions or financial loss.