Evaluate

$\int \frac{x}{\sqrt{x-4}} d x$



Use the substitution $u=x-4$.


ASolve $u=x-4$ for $x$.
BFind $d u$ and solve for $d x$.
CRewrite every part of the integral in terms of $u$.
DSimplify and evaluate the resulting integral.

Verified Answer :

  • Solve the substitution \(u = x - 4\) for \(x\) to get \(x = u + 4\) and note that \(dx = du\).
  • Rewrite the integral \(\int \frac{x}{\sqrt{x-4}} \, dx\) as \(\int \frac{u+4}{\sqrt{u}} \, du\).
  • Simplify the integrand to \(u^{1/2} + 4u^{-1/2}\) and integrate using the power rule to obtain \(\frac{2}{3}u^{3/2} + 8u^{1/2} + C\).
  • Substitute \(u = x - 4\) back into the result to find the final integral: \(\boxed{\frac{2}{3}(x-4)^{3/2} + 8\sqrt{x-4} + C}\).

Explanation

  1. Problem Analysis and Substitution Setup

The goal is to evaluate the indefinite integral \(\int \frac{x}{\sqrt{x-4}} \, dx\) using the method of u-substitution. We are given the substitution \(u = x - 4\). We must first express all variables in the integral in terms of \(u\), integrate, and then convert back to \(x\).

  1. Substitution and Rewriting the Integral

First, we solve the given substitution \(u = x - 4\) for \(x\), which gives:
\[ x = u + 4 \]
Next, we find the differential \(du\). Taking the derivative of \(u = x - 4\) with respect to \(x\) gives \(\frac{du}{dx} = 1\), which implies:
\[ du = dx \]
Now we substitute \(x = u + 4\) and \(dx = du\) into the original integral:
\[ \int \frac{x}{\sqrt{x-4}} \, dx = \int \frac{u+4}{\sqrt{u}} \, du \]

  1. Evaluating the Integral

Now we simplify the integrand \(\frac{u+4}{\sqrt{u}}\) by splitting the fraction:
\[ \int \left( \frac{u}{\sqrt{u}} + \frac{4}{\sqrt{u}} \right) \, du = \int (u^{1 - 1/2} + 4u^{-1/2}) \, du = \int (u^{1/2} + 4u^{-1/2}) \, du \]
Applying the power rule for integration \(\int u^n \, du = \frac{u^{n+1}}{n+1} + C\) (where \(n eq -1\)):
\[ \int u^{1/2} \, du = \frac{u^{3/2}}{3/2} = \frac{2}{3}u^{3/2} \]
\[ \int 4u^{-1/2} \, du = 4 \left( \frac{u^{1/2}}{1/2} \right) = 8u^{1/2} \]
Combining these, we get:
\[ \frac{2}{3}u^{3/2} + 8u^{1/2} + C \]

  1. Final Answer and Back-Substitution

Finally, substitute \(u = x - 4\) back into the expression:
\[ \frac{2}{3}(x-4)^{3/2} + 8(x-4)^{1/2} + C \]
This can be factored further or left in this form:
\[ \frac{2}{3}(x-4)^{1/2} (x-4 + 12) + C = \frac{2}{3}(x-4)^{1/2} (x+8) + C \]
The integral evaluates to \(\boxed{\frac{2}{3}(x-4)^{3/2} + 8\sqrt{x-4} + C}\).

Examples

In fields like fluid dynamics or engineering, you often need to calculate work done by pressure or force over a distance. If the force applied varies with the displacement in a non-linear way, such as \(F(x) = \frac{x}{\sqrt{x-4}}\), integration is essential to find the total energy or work. Using techniques like substitution helps simplify complex expressions into solvable forms, allowing for precise design and performance analysis.