- Evaluate each multiplication expression: \(\frac{9}{7}\), \(2\), \(0.375\), and \(2.7\).
- Compare each result to the given value in the "PRODUCT" column, which is 3.
- Identify that all expressions are strictly less than 3, meaning the appropriate inequality for every entry is \(3 \cdot \frac{n}{d} < 3\).
- The final table correctly reflects these inequalities, establishing 3 as a consistent upper bound.
Explanation
- Analyzing the Expressions and the Table Structure
We are given a table with four rows of expressions. Each expression is of the form \(3 \cdot \frac{n}{d}\). Let us evaluate each expression:
- For \(3 \cdot \frac{3}{7}\): \(\frac{9}{7} \approx 1.2857\)
- For \(3 \cdot \frac{2}{3}\): \(\frac{6}{3} = 2\)
- For \(3 \cdot \frac{1}{8}\): \(\frac{3}{8} = 0.375\)
- For \(3 \cdot \frac{9}{10}\): \(\frac{27}{10} = 2.7\)
We observe that in each case, the value of the expression is strictly less than 3. The "PRODUCT" column lists the number 3 for all rows, which serves as a common upper bound for these expressions. Therefore, we can express the relationship between each problem and this upper bound as an inequality.
- Determining the Missing Entries
Since every evaluated expression results in a value smaller than 3, we can define the "INEQUALITY" for each row as the comparison between the expression and the given upper bound of 3. The relationship is consistent across all entries, as each expression \(E_i\) satisfies the condition \(E_i < 3\). Thus, we fill the "INEQUALITY" column with \(3 \cdot \frac{n}{d} < 3\).
- Finalizing the Results
The completed table is as follows:
| PROBLEM | INEQUALITY | PRODUCT |
| :--- | :--- | :--- |
| \(3 \cdot \frac{3}{7}\) | \(3 \cdot \frac{3}{7} < 3\) | 3 |
| \(3 \cdot \frac{2}{3}\) | \(3 \cdot \frac{2}{3} < 3\) | 3 |
| \(3 \cdot \frac{1}{8}\) | \(3 \cdot \frac{1}{8} < 3\) | 3 |
| \(3 \cdot \frac{9}{10}\) | \(3 \cdot \frac{9}{10} < 3\) | 3 |
The reconciliation of the "PRODUCT" column values (being 3) is that 3 acts as the common threshold or upper limit for all the given multiplication expressions. All calculations show each result is strictly less than this limit.
Examples
In logistics and warehouse management, you often have a maximum load capacity for a transport container. If the maximum capacity is 3 tons, and you have several smaller packages weighing \(3 \cdot \frac{3}{7}\) tons, \(3 \cdot \frac{2}{3}\) tons, and so on, you can model the safety condition as an inequality. By identifying that each load is less than the capacity (\(< 3\)), you ensure that no individual shipment exceeds the limit, maintaining the safety of the transport process. This illustrates how inequalities provide a simple framework for verifying constraints in real-world scenarios.