Verified Answer :

  • Apply the distributive property to the parentheses: \(\frac{1}{2}(\frac{1}{4}x + 10) = \frac{1}{8}x + 5\).
  • Combine the variable terms: \(\frac{5}{8}x + \frac{1}{8}x = \frac{6}{8}x = \frac{3}{4}x\).
  • Add the constant term to the result to obtain the final simplified expression \(\boxed{\frac{3}{4}x + 5}\).

Explanation

  1. Analyzing the Expression

To simplify the expression \(\frac{5}{8} x + \frac{1}{2} \left(\frac{1}{4} x + 10\right)\), we first analyze the structure. The expression consists of a term \(\frac{5}{8} x\) added to a product involving a scalar multiplication of a binomial. Our goal is to expand the parentheses and collect like terms to arrive at the simplest form.

  1. Distributing the Term

The first step is to apply the distributive property to the term \(\frac{1}{2} \left(\frac{1}{4} x + 10\right)\). By multiplying \(\frac{1}{2}\) by each term inside the parentheses, we get:
\[\frac{1}{2} \times \left(\frac{1}{4} x\right) + \frac{1}{2} \times 10 = \frac{1}{8} x + 5\]
Now, substitute this back into the original expression:
\[\frac{5}{8} x + \frac{1}{8} x + 5\]

  1. Combining Like Terms and Final Simplification

Now, we combine the terms involving \(x\). Adding the coefficients \(\frac{5}{8}\) and \(\frac{1}{8}\) gives:
\[\frac{5}{8} x + \frac{1}{8} x = \left(\frac{5+1}{8}\right) x = \frac{6}{8} x\]
Simplifying the fraction \(\frac{6}{8}\) by dividing both the numerator and the denominator by their greatest common divisor, which is 2, we obtain \(\frac{3}{4}\). Thus, the combined term is \(\frac{3}{4} x\). Adding the constant 5, the fully simplified expression is \(\frac{3}{4} x + 5\).

Examples

Simplifying algebraic expressions is a foundational skill used in fields like physics and engineering to reduce complex formulas into manageable ones. For example, if you are calculating the total cost of a project involving a base fee and a variable cost per unit, such as \(\text{Cost} = \frac{5}{8}x + \frac{1}{2}(\frac{1}{4}x + 10)\), simplifying it to \(\frac{3}{4}x + 5\) makes it much easier to estimate the cost for any number of units \(x\). This helps in quick decision-making and budgeting.