- The problem asks to identify the correct equation to solve a system, likely involving the intersection of \(y = x\) and \(y = \frac{k}{x}\).
- By equating \(y = x\) and \(y = \frac{9}{x}\), we derive the equation \(x = \frac{9}{x}\).
- This equation serves as the critical step for finding the intersection points of the system.
- Therefore, the correct choice is \(\boxed{x = \frac{9}{x}}\).
Explanation
- Analyzing the Problem and Options
The problem asks us to identify an equation that helps solve a system of equations. While a specific system is not explicitly stated in the provided text, we can analyze the structure of the options to deduce the intended system. The choices provided are:
\(x = \frac{3}{x}\)
\(x = \frac{9}{x}\)
\(0 = \frac{3}{x} + x\)
\(0 = \frac{9}{x} + x\)
Each of these equations represents a step in finding the intersection points of a line and a hyperbola, specifically a system of the form \(y = x\) and \(y = \frac{k}{x}\). Setting the two expressions for \(y\) equal to each other gives \(x = \frac{k}{x}\). This is a standard procedure for finding the intersection of two graphs.
- Solving the System and Identifying the Correct Equation
Let us consider the typical system \(y = x\) and \(y = \frac{9}{x}\). To find the intersection points, we equate the two expressions for \(y\):
\[x = \frac{9}{x}\]
Multiplying both sides by \(x\) (assuming \(x
eq 0\)), we get:
\[x^2 = 9\]
The solutions to this are \(x = 3\) and \(x = -3\).
Comparing this to the given options, the equation \(x = \frac{9}{x}\) is the correct intermediate step to solve this system. The other options either represent a different constant (\(k=3\)) or involve a sign change that would imply a system like \(y = x\) and \(y = -\frac{9}{x}\) (which would lead to \(x^2 = -9\), having no real solutions). Therefore, \(x = \frac{9}{x}\) is the most standard and likely intended equation for finding the intersection of \(y = x\) and \(y = \frac{9}{x}\).
Examples
In real-world applications, identifying the intersection point of two functions is crucial in fields like economics (finding the equilibrium point between supply and demand curves) or physics (calculating when two objects meet). For example, if supply is given by \(y = x\) and demand is given by \(y = \frac{9}{x}\), solving \(x = \frac{9}{x}\) allows businesses to determine the price at which the quantity supplied equals the quantity demanded, leading to market equilibrium. Understanding how to set up and solve these equations is a fundamental skill in quantitative modeling.