How will this system at equilibrium be affected by each of the conditions stated here?



$2 H _2(g)+ O _2(g) \leftrightarrow 2 H _2 O (g)+$ heat


  1. removal of $H _2 O$
  2. addition of $O _2$
  3. decrease in pressure
  4. increase in temperature

Verified Answer :

  • The system shifts toward the products (right) when removing \(H_2O\) to replenish the substance.
  • The system shifts toward the products (right) when adding \(O_2\) to consume the excess reactant.
  • The system shifts toward the reactants (left) when decreasing pressure because there are more moles of gas on the reactant side.
  • The system shifts toward the reactants (left) when increasing temperature because the reaction is exothermic and shifts to consume the extra heat.
  • Final summary: \(\boxed{\text{1. Shift right, 2. Shift right, 3. Shift left, 4. Shift left}}\)

Explanation

  1. Analysis of the Equilibrium System

The chemical reaction provided is:
\[2H_2(g) + O_2(g) \rightleftharpoons 2H_2O(g) + \text{heat}\]
This reaction represents the synthesis of water from hydrogen and oxygen, which is an exothermic process because energy (heat) is released as a product. The system involves gaseous species on both sides. Specifically, there are \(2 + 1 = 3\) moles of gas on the reactant side and \(2\) moles of gas on the product side. According to Le Chatelier's Principle, when a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the system adjusts its position of equilibrium to counteract the applied change.

  1. Removal of \(H_2O\)

When a product like \(H_2O(g)\) is removed from the reaction mixture, the concentration of that product decreases. According to Le Chatelier's Principle, the equilibrium will shift to counteract this reduction by favoring the forward reaction, which produces more \(H_2O\). Therefore, the equilibrium shifts to the right.

  1. Addition of \(O_2\)

Adding \(O_2(g)\) increases the concentration of one of the reactants. To relieve this stress, the system consumes the excess oxygen by shifting the equilibrium toward the products. This results in the forward reaction being favored, and the equilibrium shifts to the right.

  1. Decrease in Pressure

A decrease in total pressure of the system causes the equilibrium to shift toward the side with the greater number of moles of gas to increase the pressure again. The reactant side has 3 moles of gaseous molecules, while the product side has 2. Thus, the equilibrium shifts to the left, favoring the formation of more reactants.

  1. Increase in Temperature

The reaction is exothermic, meaning heat is released as a product. Increasing the temperature provides more heat to the system. According to Le Chatelier's Principle, the system will shift in a way to absorb this extra energy by favoring the endothermic direction. Since the reverse reaction is endothermic, the equilibrium shifts to the left, which consumes the added heat and produces more reactants.

Examples

Le Chatelier's Principle is vital in industrial chemical manufacturing. For example, in the production of ammonia (Haber Process), chemists manipulate temperature and pressure to ensure the highest possible yield of the product. By understanding how to shift the equilibrium towards the desired products, companies can increase production efficiency and minimize waste, which is essential for both economic viability and sustainability in chemical engineering.