Simplify the expression $\left(\frac{1}{4 a b}\right)^{-2}$. Assume $a
eq 0, b
eq 0$.


A$-\frac{1}{16 a^2 b^2}$
B$\frac{a^2 b^2}{4}$
C$-16 a^2 b^2$
D$16 a^2 b^2$

Verified Answer :

  • Apply the negative exponent rule: \(\left(\frac{x}{y}\right)^{-n} = \left(\frac{y}{x}\right)^n\).
  • Simplify the fraction: \(\left(\frac{1}{4ab}\right)^{-2} = (4ab)^2\).
  • Expand the squared term using the power of a product rule: \((4ab)^2 = 16a^2b^2\).
  • The final simplified expression is \(\boxed{16a^2b^2}\).

Explanation

  1. Understanding the Problem and Exponent Properties

We are asked to simplify the expression \(\left(\frac{1}{4ab}\right)^{-2}\) given that \(a eq 0\) and \(b eq 0\). The expression involves a power with a negative exponent, so we should recall the relevant properties of exponents. Specifically, the negative exponent property states that \(\left(\frac{x}{y}\right)^{-n} = \left(\frac{y}{x}\right)^n\) for any non-zero \(x\) and \(y\).

  1. Rewriting with a Positive Exponent

Using the property \(\left(\frac{x}{y}\right)^{-n} = \left(\frac{y}{x}\right)^n\), we can rewrite the original expression \(\left(\frac{1}{4ab}\right)^{-2}\) by taking the reciprocal of the base and changing the sign of the exponent to positive. This gives us:
\[\left(\frac{1}{4ab}\right)^{-2} = \left(\frac{4ab}{1}\right)^2 = (4ab)^2\]

  1. Expanding the Expression

Now we apply the power of a product rule, which states that \((xyz)^n = x^n y^n z^n\). Applying this to our expression \((4ab)^2\), we get:
\[(4ab)^2 = 4^2 \times a^2 \times b^2\]
Calculating the square of the constant 4 gives \(4^2 = 16\). Therefore:
\[(4ab)^2 = 16a^2b^2\]

  1. Comparison and Conclusion

Comparing our result \(16a^2b^2\) with the given options, we find it matches the fourth choice:

  • \(-\frac{1}{16a^2b^2}\)
  • \(\frac{a^2b^2}{4}\)
  • \(-16a^2b^2\)
  • \(16a^2b^2\)

The simplified form is \(16a^2b^2\), so the correct answer is \(\boxed{16a^2b^2}\).

Examples

This expression simplification is common in physics and engineering, such as calculating the area of a surface or the square of physical constants in formulas. For instance, if you have a physical scaling factor \(k = (4ab)^{-1}\) and need to find the inverse-square of that factor, you are essentially calculating \((k^{-1})^2 = (4ab)^2\), which is a common step in normalizing data or calculating energy flux where quantities depend on the square of inverse dimensions.