Does the point $(-1, \sqrt{15})$ lie on the circle centered at the origin and containing the point $(0,4)$? Explain.
ANo, because the equation for the circle is $x^2+y^2=4$ and $(-1)^2+(\sqrt{15})^2
eq 4$.
BYes, because the equation for the circle is $x^2+y^2=16$ and $(-1)^2+(\sqrt{15})^2=16$.
CYes, because the equation for the circle is $x^2+y^2=4$ and $(-1)^2+(\sqrt{15})^2=4$.
DNo, because the equation for the circle is $x^2+y^2=16$ and $(-1)^2+(\sqrt{15})^2
eq 16$.
ANo, because the equation for the circle is $x^2+y^2=4$ and $(-1)^2+(\sqrt{15})^2
BYes, because the equation for the circle is $x^2+y^2=16$ and $(-1)^2+(\sqrt{15})^2=16$.
CYes, because the equation for the circle is $x^2+y^2=4$ and $(-1)^2+(\sqrt{15})^2=4$.
DNo, because the equation for the circle is $x^2+y^2=16$ and $(-1)^2+(\sqrt{15})^2