If $q(x)$ is a quadratic with a discriminant $=-1$, how many solutions and what type of solutions does $q(x)$ have?


A2 complex solutions
B2 real solutions
C1 complex solution
D1 real solution

Verified Answer :

  • The discriminant \(D = b^2 - 4ac\) determines the nature of the roots of a quadratic equation.
  • Since \(D = -1 < 0\), the roots are given by \(\frac{-b \pm \sqrt{-1}}{2a} = \frac{-b \pm i}{2a}\).
  • These roots are two distinct complex numbers.
  • The correct choice is \(\boxed{\text{A}}\).

Explanation

  1. Analysis of the Quadratic Discriminant

The discriminant of a quadratic function \(q(x) = ax^2 + bx + c\) is given by the expression \(D = b^2 - 4ac\). This value is crucial because it directly determines the nature of the roots of the quadratic equation \(q(x) = 0\), as seen in the quadratic formula:
\[x = \frac{-b \pm \sqrt{D}}{2a}\]
In our specific case, we are given that the discriminant \(D = -1\). We need to determine the number and type of solutions for the equation \(q(x) = 0\).

  1. Determining the Nature of the Solutions

Since the discriminant \(D = -1\) is less than zero, the square root of the discriminant, \(\sqrt{D}\), involves the square root of a negative number. Specifically, \(\sqrt{-1} = i\), where \(i\) is the imaginary unit. Substituting this into the quadratic formula, we get:
\[x = \frac{-b \pm \sqrt{-1}}{2a} = \frac{-b \pm i}{2a}\]
This yields two distinct solutions:
\[x_1 = \frac{-b}{2a} + \frac{1}{2a}i \quad \text{and} \quad x_2 = \frac{-b}{2a} - \frac{1}{2a}i\]
Since \(i\) is present, these roots are complex numbers. Furthermore, because the \(\pm\) sign allows for two different values (provided \(a eq 0\)), we have two distinct complex solutions.

  1. Conclusion

Based on our analysis, a quadratic equation with a discriminant of \(-1\) will always result in two distinct, conjugate complex solutions. Comparing this to the provided choices:

  • A. 2 complex solutions
  • B. 2 real solutions
  • C. 1 complex solution
  • D. 1 real solution

The correct option is A. Therefore, the quadratic \(q(x)\) has two complex solutions. Final answer: \(\boxed{\text{A}}\).

Examples

In electronics and signal processing, engineers often encounter systems described by differential equations whose characteristic equations have negative discriminants. This leads to complex roots, which represent oscillating behavior (like a damped harmonic oscillator). Knowing how to identify that a negative discriminant results in complex solutions allows engineers to predict that the system will exhibit underdamped oscillations rather than steady-state decay or instability.