Verified Answer :

  • Perform the prime factorization of 50: \(50 = 25 \times 2\).
  • Apply the radical property \(\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}\).
  • Simplify the expression: \(\sqrt{25} \times \sqrt{2} = 5\sqrt{2}\).
  • The simplest radical form is \(\boxed{5\sqrt{2}}\).

Explanation

  1. Understanding the Problem and Radicand Analysis

To simplify the radical \(\sqrt{50}\), we need to express the radicand (the number inside the square root) as a product of a perfect square and another integer. The goal is to extract the largest perfect square factor from the number 50. A perfect square is an integer that can be expressed as the square of another integer, such as \(1, 4, 9, 16, 25, 36, 49, \dots\). We check which of these squares divides 50.

  1. Simplifying the Radical

To find the perfect square factors of 50, we can look at its prime factorization.
We divide 50 by the smallest prime numbers:
\[50 = 2 \times 25\]
Since 25 is a perfect square (because \(5^2 = 25\)), we can rewrite the expression as:
\[\sqrt{50} = \sqrt{25 \times 2}\]
Using the product property of radicals, which states that \(\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}\) for \(a, b \ge 0\), we have:
\[\sqrt{25 \times 2} = \sqrt{25} \times \sqrt{2}\]
Since \(\sqrt{25} = 5\), the expression simplifies to \(5\sqrt{2}\). This is the simplest radical form because 2 has no perfect square factors other than 1.

  1. Conclusion

The simplest radical form of \(\sqrt{50}\) is \(5\sqrt{2}\).
The final answer is \(\boxed{5\sqrt{2}}\).

Examples

Simplest radical forms are essential in various fields, such as architecture and construction, where precise measurements are required. For instance, if you are designing a square plot of land with an area of 50 square meters, you would need to calculate the side length. The side length is \(\sqrt{50}\) meters. Expressing this as \(5\sqrt{2}\) meters allows for more accurate estimations and easier calculations when dealing with other measurements in the design. Understanding how to simplify square roots helps in working with exact values rather than long, imprecise decimals.