Which explains how to find the quotient of the given division?
$\frac{-3 \frac{1}{3}}{\frac{4}{9}}$
AWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{9}{4}$. The quotient is $-7 \frac{6}{12} = -7 \frac{1}{2}$.
BWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{4}{9}$. The quotient is $-1 \frac{13}{27}$.
CWrite $-3 \frac{1}{3}$ as $-\frac{13}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{13}{3} \times \frac{9}{4}$. The quotient is $-9 \frac{3}{4}$.
DWrite $-3 \frac{1}{3}$ as $-\frac{9}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{9}{3} \times \frac{4}{9}$. The quotient is $-1 \frac{1}{3}$.
$\frac{-3 \frac{1}{3}}{\frac{4}{9}}$
AWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{9}{4}$. The quotient is $-7 \frac{6}{12} = -7 \frac{1}{2}$.
BWrite $-3 \frac{1}{3}$ as $-\frac{10}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{10}{3} \times \frac{4}{9}$. The quotient is $-1 \frac{13}{27}$.
CWrite $-3 \frac{1}{3}$ as $-\frac{13}{3}$, and find the reciprocal of $\frac{4}{9}$ as $\frac{9}{4}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{13}{3} \times \frac{9}{4}$. The quotient is $-9 \frac{3}{4}$.
DWrite $-3 \frac{1}{3}$ as $-\frac{9}{3}$. Then, rewrite $\frac{-3 \frac{1}{3}}{\frac{4}{9}}$ as $-\frac{9}{3} \times \frac{4}{9}$. The quotient is $-1 \frac{1}{3}$.