The distance between 2 points P(a, b) and Q(c,d) is given by the formula:
\(\displaystyle{d= \sqrt{(b-d)^2+(a-c)^2}\),
Apply the formula for the points M(6, 16) and Z(-1, 14):
\(\displaystyle{d= \sqrt{(16-14)^2+(6-(-1))^2}= \sqrt{2^2+7^2}= \sqrt{4+49}= \sqrt{53}\approx 7.28\)
which rounded to the nearest tenth is 7.3 (units)
Answer: 7.3 units