Verified Answer :

leumitica

\(\frac{-3}{4q}=12\)
Multiply by q to eliminate var in denominator 
\(\frac{ ot q*(3)}{4 ot q} =q*12\)
\(q= \frac{-3}{4} =q*12\)
Common denominator is 4
\(\frac{ ot 4(-3)}{ ot 4} =4q*12\)
\(-3=4q*12\)
\(-3=48q\)
Divide  by 48
\(q=\frac{ ot 3}{ ot 4 ot 8}\)
\(q=-16\)
The answer is: \(q=-16\)

antonio9990

\(\text{We know: } \\ \boxed{\frac{\ -3\ }{\ 4\ }*q=12 } \\ \\ q=12: \frac{\ -3\ }{\ 4\ } \\ \\ q=12* \frac{\ 4\ }{\ -3\ } \\ \\ q= \frac{\ 48\ } {\ -3\ } \\ \\ q=-16 \\ ********** \\ \\ \text{Check:}\\ \\ \boxed{ \frac{-3}{4}*-16=12 } \\ \\ \frac{48}{4} =12 \ TRUE\)

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