\(\frac{-1}{8c} =2\) This requires that c ≠ 0 , meaning c≠0 \(\frac{-1}{8c} =2\) Multiply by x to eliminate var in denominator \(\frac{
ot c*(-1)}{ 8
ot c} =c*2\) \(\frac{-1}{8} =c*2\) Common denominator is 8 \(\frac{
ot 8(-1)}{
ot 8} =8c*2\) \(-1=8c*2\) \(-1=16c\) \(x=-16\) The answer is: b. -16
