Verified Answer :

Julik

\(\\ sin^2(x)-sin(x)=0 \\ sinx(sinx-1)=0 \\ \\ sinx=0 \\ x= \pi k~~k \in Z \\ x=0 \\ \\ sin(x)-1=0 \\ sin(x)=1 \\ x= \frac{ \pi }{2} +2 \pi k~~k \in Z\)



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