(10y^3+20y^2+55y)/5y
( 10y^3 + 20y^2 +55y ) / 5y = 2y^2 + 4y +11And then depending on if the equation is set to zero in the problem, just factor or use the quadratic formula on the quadratic equation that is left.
Answer:
2y^2+4y+11
Step-by-step explanation: