A soccer ball is placed 12 feet away from a goal post that measures 8ft high. You kick the ball and it hits the crossbar at the top the goal. What was the angle of elevation of you kick?

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Ryan2 Ryan2 · Answer 1 · 2014-07-11T20:45:00-04:00

\(tg(\theta)=\frac{8}{12}\\ \\ tg(\theta)=0.666... \rightarrow \theta\approx35^o\)

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AFOKE88 AFOKE88 · Answer 2 · 2022-02-18T06:00:27-05:00

The angle of elevation at which he kicks the ball is; 36.89°

We are told that the ball is 12 ft away and so we will consider it to be the horizontal distance.

The post is 8 ft high and so we will consider it to be the vertical distance.

Thus, we can use trigonometric ratio to find the angle of elevation. Thus;

tan θ = 8/12

θ = tan⁻¹0.75

θ = 36.89°

In conclusion the angle of elevation at which he kicks the ball is 36.89°

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