Find geometric mean between 3 and 6
\(geometric\ mean\ between \ a\ and\ b\ = \sqrt{a\cdot b} \\----------------------\\\\geometric\ mean= \sqrt{3\cdot6} = \sqrt{3\cdot3\cdot2} =3\cdot \sqrt{2}\)
Call the geometric mean ' G '.Then (3 / G) = (G / 6)This is a proportion, and may be "cross-multiplied":G² = 18G = √18 = about 4.2426... (rounded)